Question

这是本网站的第一个问题，我想按获得的积分排序，团队排名，有任何错误，但短路不起作用。我希望你的帮助能够克服这个问题

Team.h

ptr = (int*) malloc(100 * sizeof(int))

Team.cpp

class Team
{
private:
    std::string t_name;
    int t_rank;

public:
    int t_points;
    Team(std::string name);
    ~Team();
    void win();
    void show(std::ostream &Flux)const;
};
std::ostream& operator<<(std::ostream &Flux, Team const &B);
bool operator<(Team const& A,Team const& B);

的main.cpp

Team::Team(string name): t_name(name), t_points(0) {}

void Team::win()
{
    t_points+=3;
}

void Team::show(std::ostream &Flux)const
{
    Flux << t_name;
}

std::ostream& operator<<(std::ostream &Flux, Team const &B)
{
    B.show(Flux);
    return Flux;
}

bool operator<(Team const& A,Team const& B){
    return A.t_points < B.t_points;
}

我编辑了我的文件以添加您提供的信息，但仍然没有回应m问题，所以我重新发布所有内容并等待更多帮助

Answer 1

由于vector<Team*>存储指针，您需要重载operator<(const Team*, const Team*) operator，如下所示：

bool operator<(const Team* left, const Team* right) {
    return left->whatever < right->whatever;
}

Answer 2

这完全没问题。但仅当SELECT C.OCD, COUNT(*) AS USED FROM DRAFT D JOIN STKRNG S ON S.DFTACCT_CANUM = D.DFTACCT_CANUM JOIN DFACCT DA ON S.DFTACCT_CANUM = DA.DFTACCT_CANUM JOIN CMPNT C ON CMPNT.OCD = DA.OWNG_OCD WHERE D.DRFT_SEQ_NUM >= (SELECT MIN(S.STK_STRT_SEQ_NUM) FROM STKRNG S WHERE D.DFTACCT_CANUM = S.DFTACCT_CANUM AND S.RANGE_USED_SW = 'N') AND D.DRFT_SEQ_NUM <= (SELECT MAX(S.STK_END_SEQ_NUM) FROM STKRNG S WHERE D.DFTACCT_CANUM = S.DFTACCT_CANUM AND S.RANGE_USED_SW = 'N') AND S.STK_TYP = 'R' AND S.RANGE_USED_SW = 'N' AND C.ST = 'FL' GROUP BY C.OCD;不是a_：

时

private

将#include <algorithm> #include <iostream> #include <vector> class A { public: A(size_t const& a) : a_(a) {}; ~A(){}; //private: size_t a_; }; bool operator<(A const& left, A const& right) { return left.a_ < right.a_; } int main() { std::vector<A*> v; v.push_back(new A(10)); v.push_back(new A(6)); v.push_back(new A(8)); for(auto const& a : v) { std::cout << a->get() << std::endl; } std::sort(v.begin(),v.end()); for(auto const& a : v) { std::cout << a->get() << std::endl; } }作为成员实施，这也将得到解决：

operator<

然后，bool operator<(A const& other) { return a_ < other.a_; }可以是私有的。

对象的排序向量不起作用

2 个答案: