Question

我是新手，这是我上学的功课。该程序假设打印从1到5（而不是5到1），到目前为止，我只能使程序从5打印到1，任何对此的帮助将是值得赞赏的。程序应该只使用while循环

#include <iostream>
#include <stdlib.h>

using namespace std;

int main (int argc, char *argv[])
{
    //if statement to check only 2 argument can be passed
    if (argc != 2)
    {
            cout << "ERROR!" << endl;
    }
    else
    {
            if (atoi(argv[1]) < 1)          //if statement to check negative numbers
            {
                    cout << "ERROR!"<< endl;
            }
            int temp = atoi(argv[1]);       //convert the number inthe character argument to integer
            int sum = 0;                    //variable declaration to find the sum passed in the while loop

    //the while loop is used to print out the numbers entered in descending order
    while (temp > 0)
    {
            cout << temp << endl;           //output numbers in the iteration
            sum = sum + temp;               //sums the number of iteration
            temp --;                        //counter, used to stop the while loop to avois an infinity loop
    }

    cout << "Sum is " << sum << endl;
    }

    return 0;

}

Answer 1

使用for循环

for(int i=1;i<=temp;i++){
        cout << i << endl;        //output numbers in the iteration
        sum = sum + i;
 }

或像这样的while循环

   int counter=1;

   while (counter<=temp)
    {
            cout << counter << endl;           //output numbers in the iteration
            sum = sum + counter;               //sums the number of iteration
            counter ++;                        //counter, used to stop the while loop to avois an infinity loop
    }

https://www.tutorialspoint.com/cplusplus/cpp_for_loop.htm

迭代计数 - 需要帮助，新编程

1 个答案: