我有查询,我想列出结果如下:
我使用了以下查询来实现它,但它没有按预期工作,并对结果ASC或DESC进行排序。
SELECT * from (SELECT eventid, eventdate,eventdates FROM events WHERE events.onlineclosingdate>curdate() order by onlineclosingdate asc) a
UNION ALL
SELECT * from (SELECT eventid, eventdate,eventdates FROM events WHERE events.onlineclosingdate<=curdate() order by onlineclosingdate desc) as c
答案 0 :(得分:2)
例如,您可能需要识别2个日期期间块并使用条件订单 给定
drop table if exists t;
create table t (id int auto_increment primary key, dt date);
insert into t (dt) values
('2017-02-01'),('2017-10-01'),('2017-01-01'),
('2016-02-01'),('2016-10-01'),('2016-01-01');
select s.id,s.dt
from
(
select 1 as srce,id,t.dt dt from t where dt > str_to_date('2016-12-31','%Y-%m-%d')
union all
select 2,id,t.dt from t where dt <= str_to_date('2016-12-31','%Y-%m-%d')
) s
order by srce asc,
case when s.srce = 1 then s.dt end asc,
case when s.srce = 2 then s.dt end desc;
+----+------------+
| id | dt |
+----+------------+
| 3 | 2017-01-01 |
| 1 | 2017-02-01 |
| 2 | 2017-10-01 |
| 5 | 2016-10-01 |
| 4 | 2016-02-01 |
| 6 | 2016-01-01 |
+----+------------+
6 rows in set (0.00 sec)
答案 1 :(得分:-1)