使用Union ALL我的sql,Order by无法正常工作

时间:2017-09-07 02:44:11

标签: mysql sql-order-by union

我有查询,我想列出结果如下:

1
2

我使用了以下查询来实现它,但它没有按预期工作,并对结果ASC或DESC进行排序。

SELECT * from (SELECT eventid, eventdate,eventdates FROM events WHERE events.onlineclosingdate>curdate() order by onlineclosingdate asc) a
UNION  ALL
SELECT * from (SELECT eventid, eventdate,eventdates FROM events WHERE events.onlineclosingdate<=curdate() order by onlineclosingdate desc) as c 

2 个答案:

答案 0 :(得分:2)

例如,您可能需要识别2个日期期间块并使用条件订单 给定

drop table if exists t;
create table t (id int auto_increment primary key, dt date);

insert into t (dt) values
('2017-02-01'),('2017-10-01'),('2017-01-01'),
('2016-02-01'),('2016-10-01'),('2016-01-01');

select s.id,s.dt 
from
(
select 1 as srce,id,t.dt dt from t where dt > str_to_date('2016-12-31','%Y-%m-%d') 
union all
select 2,id,t.dt from t where dt <= str_to_date('2016-12-31','%Y-%m-%d') 
) s
order by srce asc,
            case when s.srce = 1 then s.dt end asc, 
            case when s.srce = 2 then s.dt end desc;

+----+------------+
| id | dt         |
+----+------------+
|  3 | 2017-01-01 |
|  1 | 2017-02-01 |
|  2 | 2017-10-01 |
|  5 | 2016-10-01 |
|  4 | 2016-02-01 |
|  6 | 2016-01-01 |
+----+------------+
6 rows in set (0.00 sec)

答案 1 :(得分:-1)

一个

中联合两个查询和分组
Origin: null

Getting result like this