Question

我有一个存储过程，其中包含以下查询：

SELECT (sum(addition)) AS [COUNT], 
MAX(CONVERT(VARCHAR(12),CREATED,102)) as [date]
FROM [TABLE_ONE]
WHERE convert(VARCHAR(12),CREATED,102) BETWEEN CONVERT(date,@startdate) AND CONVERT(date,@enddate)
AND [ServiceID]=@serid
GROUP BY CONVERT(VARCHAR(12),CREATED,102) 
ORDER BY  CONVERT(VARCHAR(12),CREATED,102)

我需要做一个union all，所以我可以得到结果的总和，但是来自两个表的，我希望结果按照相同的方式进行分组和排序。< / p>

这不起作用：

SELECT (sum(addition)) AS [COUNT], 
MAX(CONVERT(VARCHAR(12),CREATED,102)) as [date]
FROM [TABLE_ONE]
WHERE convert(VARCHAR(12),CREATED,102) BETWEEN CONVERT(date,@startdate) AND CONVERT(date,@enddate)
AND [ServiceID]=@serid
GROUP BY CONVERT(VARCHAR(12),CREATED,102) 
ORDER BY  CONVERT(VARCHAR(12),CREATED,102)  

UNION ALL

SELECT (sum(addition)) AS [COUNT], 
MAX(CONVERT(VARCHAR(12),CREATED,102)) as [date]
FROM [TABLE_TWO]
WHERE convert(VARCHAR(12),CREATED,102) BETWEEN CONVERT(date,@startdate) AND CONVERT(date,@enddate)
AND [ServiceID]=@serid
GROUP BY CONVERT(VARCHAR(12),CREATED,102) 
ORDER BY  CONVERT(VARCHAR(12),CREATED,102)

我想订购整体结果，并按日期分组。

Answer 1

您可以在group by之后应用order by和union all：

SELECT  (SUM(addition)) AS [COUNT], MAX([date]) AS [max_date]
FROM    (SELECT addition, CONVERT(VARCHAR(12),CREATED,102)) as [date]
         FROM   [TABLE_ONE]
         WHERE  CONVERT(VARCHAR(12),CREATED,102) 
                    BETWEEN CONVERT(date,@startdate) AND 
                            CONVERT(date,@enddate)
                AND [ServiceID]=@serid 
         UNION ALL
         SELECT addition, (CONVERT(VARCHAR(12),CREATED,102)) as [date]
         FROM   [TABLE_TWO]
         WHERE  CONVERT(VARCHAR(12),CREATED,102) 
                    BETWEEN CONVERT(date,@startdate) AND 
                            CONVERT(date,@enddate)
                AND [ServiceID]=@serid) t
GROUP BY [date]
ORDER BY 2

使用UNION ALL进行分组和排序

1 个答案: