Question

我试图提取每小时昨天发生的所有交易的数量。我不想今天做交易。但我似乎无法在这种情况下获得正确的代码。

到目前为止我的代码：

SELECT  CAST(TransDT as DATE) as 'TransDate' 
       ,CAST(DATEPART(Hour, TransDT) as varchar) + ':00' as 'Hour' 
       ,LaneID
       ,Direction
       ,COUNT(*) as 'Ct'

FROM Traffic_analysis

WHERE TransDT >= DATEADD (DAY, -1 , SYSDATETIME())
  AND TransDT < CAST(DATEPART(DAY, SYSDATETIME()) as int) --This is the faulty line.

GROUP BY CAST(TransDT as DATE), DATEPART(Hour, TransDT), LaneID, Direction
ORDER BY CAST(TransDT as DATE) ASC

如果我评论整个错误的行，我会得到昨天和今天的结果。我昨天只需要结果。

我要做的是显示一个带有图表的报告，该图表显示每个时段，每个车道，每个方向的流量。将所有NB流量放在一列中并将所有SB流量放在另一列中会更好。也许是UNION加入？

Answer 1

如果我理解您的问题，您可以执行以下操作：

Where   TransDT >= Convert(Date, DateAdd(Day, -1, GetDate())
And     TransDT < Convert(Date, GetDate())

Answer 2

你试过这个吗？

WHERE cast(TransDT as date) > DATEADD (DAY, -2 , cast(SYSDATETIME() as date))
  AND cast(TransDT as date) <= DATEADD (DAY, -1 , cast(SYSDATETIME() as date))

实际上，我认为这是理所当然的。

WHERE cast(TransDT as date) = DATEADD (DAY, -1 , cast(SYSDATETIME() as date))

Answer 3

TransDT是一个日期，但是您与INT进行比较。

尝试类似的东西：

TransDT = CAST(SYSDATETIME() AS DATE)

如何在SQL Server 2014中获取昨天和今天之间的事务？

3 个答案: