Question

SELECT  * FROM att_record2 WHERE  DATE(row_datentime)=DATE_SUB(CURDATE(), INTERVAL 1 DAY)  
AND out_datentime="0000-00-00 00:00:00" AND in_datentime!="0000-00-00 00:00:00"

我想获取今天和昨天的数据我只批准昨天的唯一演出，但我想今天和昨天都请帮助我

Answer 1

好的，您可以获得昨天和今天的以下功能：

mysql> select curdate() as today;
+------------+
| today      |
+------------+
| 2019-06-12 |
+------------+
1 row in set (0.00 sec)

mysql> select curdate() - interval 1 day as yesterday;
+------------+
| yesterday  |
+------------+
| 2019-06-11 |
+------------+
1 row in set (0.00 sec)

mysql> select curdate() + interval 1 day as tomorrow;
+------------+
| tomorrow   |
+------------+
| 2019-06-13 |
+------------+
1 row in set (0.00 sec)

因此，完整的SQL：

select  
    * 
from 
    att_record2 
where  
    date(row_datentime) >= curdate() - interval 1 day
    and date(row_datentime) <= curdate()
    and out_datentime='0000-00-00 00:00:00'
    and in_datentime!='0000-00-00 00:00:00'

Answer 2

使用> =和<=如下

 SELECT  * FROM att_record2 WHERE row_datentime >= NOW() - INTERVAL 1 DAY  AND row_datentime  <= NOW() AND out_datentime="0000-00-00 00:00:00" AND in_datentime!="0000-00-00 00:00:00"

从mysql获取今天和昨天的数据

2 个答案: