打印到CSV时，Python会跳过行

Question

我正在尝试创建.csv文件。

出于某种原因，它会在打印条目之前跳过一行。

这是输出

但这就是我需要的东西

下面是代码。显然if line != "":无效

import csv

#-----------------------------------
def csv_writer(data,path):
    """
    Write data to a CSV file path
    """
    with open(path, "w") as csv_file:
        writer = csv.writer(csv_file, delimiter=',')
        for line in data:
            if line != "":
                writer.writerow(line)

#-----------------------------------
if __name__ == "__main__":
    data = ["first_name,last_name,city".split(","),
            "Tyrese,Hirthe,Strackeport".split(","),
            "Jules,Dicki,Lake Nickolasville".split(","),
            "Dedric,Medhurst,Stiedemannberg".split(",")
            ]
    path = "output.csv"
    csv_writer(data,path)

Answer 1

某些python版本（在Windows上）与with open(path, "w") as csv_file:存在问题。一个spurious carriage return char is inserted，在每行后面创建一个空行。

您必须按照文档中的说明添加newline=""。 Python 3：

with open(path, "w",newline="") as csv_file:
    writer = csv.writer(csv_file, delimiter=',')

至于python 2：

with open(path, "wb") as csv_file:
    writer = csv.writer(csv_file, delimiter=',')

另见：

• portable way to write csv file in python 2 or python 3
• csv writer expected byte like and space between rows

（请注意，Windows上的最新Python版本不再需要此版本，但文档会继续说明）

Answer 2

当您打开文件时，需要使用空字符串传递关键字参数换行符。这将阻止在行之间添加换行符。你的功能应该是：

def csv_writer(data,path):
"""
Write data to a CSV file path
"""
with open(path, "w", newline = '') as csv_file:
    writer = csv.writer(csv_file, delimiter=',')
    for line in data:
        if line != "":
            writer.writerow(line)

请注意，这只是Windows上的一个问题。