我目前正在使用此代码:
import pandas as pd
AllDays = ['a','b','c','d']
TempDay = pd.DataFrame( np.random.randn(4,2) )
TempDay['Dates'] = AllDays
TempDay.to_csv('H:\MyFile.csv', index = False, header = False)
但是当它打印时,它会在带有标题行的日期之前打印数组。我正在寻找在TemperatureArray之前打印日期而没有标题行。
编辑: 该文件带有TemperatureArray,后跟日期:[TemperatureArray,Date]。
-0.27724356949570034,-0.3096554106726788,a
-0.10619546908708237,0.07430127684522048,b
-0.07619665345406437,0.8474460146082116,c
0.19668718143436803,-0.8072994364484335,d
我打算打印:[Date TemperatureArray]
a,-0.27724356949570034,-0.3096554106726788
b,-0.10619546908708237,0.07430127684522048
c,-0.07619665345406437,0.8474460146082116
d,0.19668718143436803,-0.8072994364484335
答案 0 :(得分:2)
pandas.Dataframe.to_csv方法有一个关键字参数header=True
可以关闭以禁用标题。
然而,它有时不起作用(来自经验)。
将其与index=False
结合使用可以解决您的问题。
例如,此代码段应解决您的问题:
TempDay.to_csv('C:\MyFile.csv', index=False, header=False)
以下是一个完整的示例,展示了如何禁用标题行:
>>> import pandas as pd
>>> import numpy as np
>>> df = pd.DataFrame(np.random.randn(6,4))
>>> df
0 1 2 3
0 1.295908 1.127376 -0.211655 0.406262
1 0.152243 0.175974 -0.777358 -1.369432
2 1.727280 -0.556463 -0.220311 0.474878
3 -1.163965 1.131644 -1.084495 0.334077
4 0.769649 0.589308 0.900430 -1.378006
5 -2.663476 1.010663 -0.839597 -1.195599
>>> # just assigns sequential letters to the column
>>> df[4] = [chr(i+ord('A')) for i in range(6)]
>>> df
0 1 2 3 4
0 1.295908 1.127376 -0.211655 0.406262 A
1 0.152243 0.175974 -0.777358 -1.369432 B
2 1.727280 -0.556463 -0.220311 0.474878 C
3 -1.163965 1.131644 -1.084495 0.334077 D
4 0.769649 0.589308 0.900430 -1.378006 E
5 -2.663476 1.010663 -0.839597 -1.195599 F
>>> # here we reindex the headers and return a copy
>>> # using this form of indexing just requires you to provide
>>> # a list with all the columns you desire and in the order desired
>>> df2 = df[[4, 1, 2, 3]]
>>> df2
4 1 2 3
0 A 1.127376 -0.211655 0.406262
1 B 0.175974 -0.777358 -1.369432
2 C -0.556463 -0.220311 0.474878
3 D 1.131644 -1.084495 0.334077
4 E 0.589308 0.900430 -1.378006
5 F 1.010663 -0.839597 -1.195599
>>> df2.to_csv('a.txt', index=False, header=False)
>>> with open('a.txt') as f:
... print(f.read())
...
A,1.1273756275298716,-0.21165535441591588,0.4062624848191157
B,0.17597366083826546,-0.7773584823122313,-1.3694320591723093
C,-0.556463084618883,-0.22031139982996412,0.4748783498361957
D,1.131643603259825,-1.084494967896866,0.334077296863368
E,0.5893080536600523,0.9004299653290818,-1.3780062860066293
F,1.0106633581546611,-0.839597332636998,-1.1955992812601897
如果您需要动态调整列,并将最后一列移到第一列,您可以执行以下操作:
# this returns the columns as a list
columns = df.columns.tolist()
# removes the last column, the newest one you added
tofirst_column = columns.pop(-1)
# just move it to the start
new_columns = [tofirst_column] + columns
# then you can the rest
df2 = df[new_columns]
这只是允许您获取当前列列表,从当前列构造Python列表,并重新索引标题,而无需事先了解标题。