使用此代码将视频从Raspberry Pi流式传输到192.168.0.6:8081 ......
[根据评论和编辑进行编辑;丹尼尔]
import numpy as np
import cv2
import socket
class VideoStreamingTest(object):
def __init__(self):
#self.server_socket = socket.socket()
#self.server_socket.bind(('192.168.0.6', 8081))
#self.server_socket.listen(0)
#self.connection, self.client_address = self.server_socket.accept()
#self.connection = self.connection.makefile('rb')
#self.streaming()
self.socket = socket.socket()
self.connection = self.socket.connect(('192.168.0.6', 8081))
#self.socket.connect(('192.168.0.6', 8081))
self.streaming()
def streaming(self):
try:
#print ("Connection from: ", self.client_address)
print ("Streaming...")
print ("Press 'q' to exit")
stream_bytes = b' '
while True:
stream_bytes += self.socket.recv(1024)
first = stream_bytes.find('\xff\xd8')
last = stream_bytes.find('\xff\xd9')
if first != -1 and last != -1:
jpg = stream_bytes[first:last + 2]
stream_bytes = stream_bytes[last + 2:]
#image = cv2.imdecode(np.fromstring(jpg, dtype=np.uint8), cv2.CV_LOAD_IMAGE_GRAYSCALE)
image = cv2.imdecode(np.fromstring(jpg, dtype=np.uint8), cv2.CV_LOAD_IMAGE_UNCHANGED)
cv2.imshow('image', image)
if cv2.waitKey(1) & 0xFF == ord('q'):
break
finally:
#self.connection.close()
self.socket.close()
if __name__ == '__main__':
VideoStreamingTest()
*但是我收到以下错误:(已编辑):( *
Streaming...
Press 'q' to exit
Traceback (most recent call last):
File "C:/Users/tiger/Desktop/take_the_stream_from_pi.py", line 48, in <module>
VideoStreamingTest()
File "C:/Users/tiger/Desktop/take_the_stream_from_pi.py", line 19, in __init__
self.streaming()
File "C:/Users/tiger/Desktop/take_the_stream_from_pi.py", line 32, in streaming
first = stream_bytes.find('\xff\xd8')
TypeError: a bytes-like object is required, not 'str'
我该如何解决这个问题? ( PS :尝试使用此程序从pi相机(在我的网络浏览器上使用192.168.0.6:8081)打开流媒体窗口到我的电脑上)
答案 0 :(得分:0)
connect_ex
返回一个整数,这是一个错误代码,如果没有错误则返回0。您需要通过套接字本身读取,而不是通过该调用的结果。
另请注意,正如文档中所述,没有read
方法;这是致电recv
。
stream_bytes += self.socket.recv(1024)
此外,正如评论中所述,出于同样的原因,您无需致电self.connection.close
。