所以,我正在尝试清理包含一些NaN值的数据框
我尝试了所有建议的方法,但似乎我无法摆脱NaN。
df = pd.read_csv('filename.tsv', delimiter='\t')
df = df[pd.notnull(df)]
df = df.dropna()
df[pd.isnull(df)]
# gives our records containing NaN (alot of them.)
我不确定我错过了什么?
更多编辑: 当我试图看到类型
heads = df[df.isnull()].head()
for idx, row in heads.iterrows():
print idx, type(row.listener_id)
此回归
0 <type 'float'>
1 <type 'float'>
2 <type 'float'>
3 <type 'float'>
4 <type 'float'>
答案 0 :(得分:1)
我认为如果需要使用布尔索引:
df = df[~df.isnull().any(axis=1)]
但更好的是仅使用:
df = df.dropna()
样品:
df = pd.DataFrame({'A':[np.nan,5,4,5,5,np.nan],
'B':[7,8,9,4,2,np.nan],
'C':[1,3,5,7,1,np.nan],
'D':[5,3,6,9,2,np.nan]})
print (df)
A B C D
0 NaN 7.0 1.0 5.0
1 5.0 8.0 3.0 3.0
2 4.0 9.0 5.0 6.0
3 5.0 4.0 7.0 9.0
4 5.0 2.0 1.0 2.0
5 NaN NaN NaN NaN
#get True for NaN
print (df.isnull())
A B C D
0 True False False False
1 False False False False
2 False False False False
3 False False False False
4 False False False False
5 True True True True
#check at least one True per row
print (df.isnull().any(axis=1))
0 True
1 False
2 False
3 False
4 False
5 True
dtype: bool
#boolen indexing with inverting `~` (need select NO NaN rows)
print (df[~df.isnull().any(axis=1)])
A B C D
1 5.0 8.0 3.0 3.0
2 4.0 9.0 5.0 6.0
3 5.0 4.0 7.0 9.0
4 5.0 2.0 1.0 2.0
#get True for not NaN
print (df.notnull())
A B C D
0 False True True True
1 True True True True
2 True True True True
3 True True True True
4 True True True True
5 False False False False
#get True if all values per row are True
print (df.notnull().all(axis=1))
0 False
1 True
2 True
3 True
4 True
5 False
dtype: bool
#boolean indexing
print (df[df.notnull().all(axis=1)])
A B C D
1 5.0 8.0 3.0 3.0
2 4.0 9.0 5.0 6.0
3 5.0 4.0 7.0 9.0
4 5.0 2.0 1.0 2.0
#simpliest solution
print (df.dropna())
A B C D
1 5.0 8.0 3.0 3.0
2 4.0 9.0 5.0 6.0
3 5.0 4.0 7.0 9.0
4 5.0 2.0 1.0 2.0