Question

我正在使用hibernate进行映射和类，但我得到了错误。我的映射是一个学生有很多学校科目。我首先使用postgres制作数据库。谢谢！

CREATE TABLE aluno
(
  idAluno serial,
  datanascimento date,
  matricula character varying(255),
  nome character varying(255),
  CONSTRAINT pkAluno PRIMARY KEY (idAluno)
);

CREATE TABLE materiaaluno
(
  idCurso serial,
  nome character varying(255),
  idAluno integer NOT NULL,
  CONSTRAINT pkMateriAluno PRIMARY KEY (idcurso),
  CONSTRAINT fkAluno FOREIGN KEY(idAluno) REFERENCES aluno(idAluno)
);

警告：＃{alunoBean.salvar（）}：java.lang.Exception：无法通过modelo.Materia.idcurso的反射getter获取字段值 javax.faces.FacesException：＃{alunoBean.salvar（）}：java.lang.Exception：无法通过modelo.Materia.idcurso的反射getter获取字段值

阿鲁诺班

package modelo;

import java.io.Serializable;
import java.util.Date;
import java.util.List;
import java.util.Objects;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.OneToMany;
import javax.persistence.Table;
import javax.persistence.Temporal;
import javax.persistence.TemporalType;

@Entity
@Table(name = "aluno")
public class Aluno implements Serializable {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "idaluno")
private Integer idaluno;

@Column(name = "nome")
private String nome;

@Temporal(TemporalType.DATE)
@Column(name = "datanascimento")
private Date datanascimento;

@Column(name = "matricula")
private String matricula;

@OneToMany(mappedBy = "aluno", cascade = CascadeType.ALL)
private List<Materia> materias;

// contructors, getters and setters

}

Materia class

package modelo;

import java.io.Serializable;
import java.util.Objects;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;

import javax.persistence.ManyToOne;
import javax.persistence.Table;

@Entity
@Table(name = "materiaaluno")
public class Materia implements Serializable {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "idcurso")
private Integer idcurso;

@Column(name = "nome")
private String nome;

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "idaluno")
private Aluno aluno;

// constructor, getters and setters
}

Answer 1

你可能忘记/误写了实体b中的二传手和吸气者 Hibernate尝试通过反射来访问字段，否则就不会这样做。

检查字段Materia

使用hibernate并获取＆＃34;无法通过反射得到字段值＆＃34;错误

1 个答案: