Question

我正在尝试通过外键过滤结果集：

createCriteria(Person.class).add(Restrictions.ne("position", 1L)).list()

但是得到这个例外：org.hibernate.PropertyAccessException: could not get a field value by reflection getter of com.example.model.Position.id

以下是必要的JPA实体（修剪到必要的字段）：

@Entity
@Table
public class Person {
    @Id
    @GeneratedValue
    private Long id;

    @ManyToOne
    @JoinColumn(nullable = false)
    @ForeignKey(name = "person_position_fkey")
    private Position position;

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public Position getPosition() {
        return position;
    }

    public void setPosition(Position position) {
        this.position = position;
    }
}

@Entity
@Table
public class Position {
    @Id
    @GeneratedValue
    private Long id;

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }
}

Answer 1

尝试Restrictions.ne("position.id", 1L)

无法通过反射getter获取字段值

1 个答案: