Question

我想创建一个以json格式显示模型内容的页面。现在我收到了一个错误，在/ app / api / get的TemplateDoesNotExist rest_framework / api.html。 models.py是

from django.db import models

# Create your models here.
class Color(models.Model):
    name = models.CharField(max_length=255)
    background_color = models.CharField(max_length=255)
    h1_color = models.CharField(max_length=255)
    p_color = models.CharField(max_length=255)

    def __str__(self):
        return self.name

serializers.py是

from .models import Color
from rest_framework import serializers


class TaskSerializer(serializers.Serializer):
    task_name = serializers.CharField(max_length=100,source='name')

    class Meta:
        model = Color
        fields = ('name',
                  'background_color',
                  'h1_color',
                  'p_color',
                  'task_name')

urls.py是

from django.conf.urls import url
from . import views

urlpatterns = [
    url(r'^$', views.index, name='index'),
    url(r'api/get',views.TaskGet.as_view(),name='task-get')
]

views.py是

from django.shortcuts import render
from .models import Color
from .forms import ColorForm
from .serializers import TaskSerializer
from rest_framework.views import APIView
from rest_framework.response import Response

from rest_framework import status

# Create your views here.
def index(request):
    d = {
        'colors': Color.objects.all(),
        'form': ColorForm(),
    }
    return render(request, 'index.html', d)

class TaskGet(APIView):
    def get(self, request, format=None):
        obj = Color.objects.all()
        serializers = TaskSerializer(obj, many=True)

        return Response(serializers.data, status.HTTP_200_OK)

我没有在任何地方写过api.html。我没有注册frest_framework目录。所以，我真的不明白为什么会发生这个错误。我怎么能解决这个问题？

追溯是

Traceback:

File "/Users/XXX/anaconda/envs/py36/lib/python3.6/site-packages/django/core/handlers/exception.py" in inner
  41.             response = get_response(request)

File "/Users/XXX/anaconda/envs/py36/lib/python3.6/site-packages/django/core/handlers/base.py" in _get_response
  217.                 response = self.process_exception_by_middleware(e, request)

File "/Users/XXX/anaconda/envs/py36/lib/python3.6/site-packages/django/core/handlers/base.py" in _get_response
  215.                 response = response.render()

File "/Users/XXX/anaconda/envs/py36/lib/python3.6/site-packages/django/template/response.py" in render
  107.             self.content = self.rendered_content

File "/Users/XXX/anaconda/envs/py36/lib/python3.6/site-packages/rest_framework/response.py" in rendered_content
  72.         ret = renderer.render(self.data, accepted_media_type, context)

File "/Users/XXX/anaconda/envs/py36/lib/python3.6/site-packages/rest_framework/renderers.py" in render
  705.         template = loader.get_template(self.template)

File "/Users/XXX/anaconda/envs/py36/lib/python3.6/site-packages/django/template/loader.py" in get_template
  25.     raise TemplateDoesNotExist(template_name, chain=chain)

Exception Type: TemplateDoesNotExist at /app/api/get/
Exception Value: rest_framework/api.html

Answer 1

确保rest_framework中的INSTALLED_APPS列表中列出了settings.py：

# Application definition

INSTALLED_APPS = [
    'django.contrib.admin',
    'django.contrib.auth',
    'django.contrib.contenttypes',
    'django.contrib.sessions',
    'django.contrib.messages',
    'django.contrib.staticfiles',

    'rest_framework'  # <<<
]

首先，更改您的task-get网址格式正则表达式：

from django.conf.urls import url

from . import views

urlpatterns = [
    # ...
    url(r'^api/get/$', views.TaskGet.as_view(), name='task-get')
    # ____^________^___________________
    # Put "begin" and "end" of the url.
]

由于您要显示所有Color，因此使用 DRF 标准库中的ListAPIView可能是更好的方法：

from rest_framework import generics

class TaskGet(generics.ListAPIView):
    serializer_class = TaskSerializer
    queryset = Color.objects.all()

如您所见，不需要实施get方法，因为这是标准GET请求，您只需指定queryset和{{1这将序列化这个集合。 DRF 会关心其余部分。

此方法将列出数据库中的所有serializer_class条目，并以JSON格式序列化。

在/ app / api / get的TemplateDoesNotExist

1 个答案: