Question

我有一个Integer类型ArrayList，我希望遍历我的列表并能够匹配当前索引项的所有重复项。

for(int i = 0; i < list.size(); i++) {
     if(list.get(i) == list.get())//stuck here

//I want to scan the list if the current element has the same value to
//other elements while ignoring the value of my current index

任何帮助将不胜感激。谢谢！

Answer 1

应该是这样的：

int currentIndex = 3;
T value = list.get(currentIndex);
Iterator<T> it = list.iterator();
for (int i = 0; it.hasNext(); i++) {
    T checkValue = it.next();
    if (i == currentIndex) continue;
    if (value != checkValue) continue;

    // whatever should take place in case of equality
}

我认为对于“重复”，你实际上是指对象在列表中的相同实例而不是对象是相等的。在这种情况下，应使用!value.equals(checkValue)（附加检查值不为空以防止异常）

Answer 2

for(int i = 0; i < list.size(); i++) {
     // I have used Equal here but you can use "==" if you need to do         // it stronge
     list.stream().filter(t->!t.equal(list.get(i))).foreach(t->{
              // do what you want to do here
     })
}

Answer 3

我会尝试更合乎逻辑的方法：

Day

在列表中查找重复项

3 个答案: