Python - 压扁不规则列表

Question

如何压缩此列表：

irr_list = [[[u'Animal Collective'], u'Lion in a Coma'], [[u'Animal Collective'], u'Hocus Pocus'], [[u'Animal Collective'], u'Vertical'], [[u'Animal Collective'], u'Natural Selection'], [[u'Animal Collective'], u'Spilling Guts'], [[u'Animal Collective'], u'Recycling']]

这个想要的输出？

output = [[u'Animal Collective', u'Lion in a Coma'], [u'Animal Collective', u'Hocus Pocus'], [u'Animal Collective', u'Vertical'], [u'Animal Collective', u'Natural Selection'], [u'Animal Collective', u'Spilling Guts'], [u'Animal Collective', u'Recycling']]

我试过了：

flattened = [val for sublist in irr_list for val in sublist]

无济于事

Answer 1

你可以试试这个：

import itertools

new_data = [list(itertools.chain.from_iterable([[b] if not isinstance(b, list) else b for b in i])) for i in irr_list]

输出：

[[u'Animal Collective', u'Lion in a Coma'], [u'Animal Collective', u'Hocus Pocus'], [u'Animal Collective', u'Vertical'], [u'Animal Collective', u'Natural Selection'], [u'Animal Collective', u'Spilling Guts'], [u'Animal Collective', u'Recycling']]

Answer 2

如果您的列表始终采用[[list, element], [list, element], ...]格式，那么您可以使用列表推导

output = [[l[0], e] for l, e in irr_list]