我有这段代码:
items = ["place", "key", "holder"]
items[1,0] = ["bottle", "my"]
items # => ["place", "bottle", "my", "key", "holder"]
"my"
如何排在第三位?
答案 0 :(得分:1)
ary[start, length] = obj or other_ary or nil → obj or other_ary or nil
items[1,0] = ["bottle", "my"]
Here, 1 is Index & Length is 0
根据文档'元素在开始时插入到数组中,如果长度为&指数为零。'
对于Ex: -
a = ['A']
a[0, 0] = [ 1, 2 ] #=> array a will be [1, 2, "A"]
同样,当Index不为零时,&长度为零'元素从给定的索引'
插入到数组中a = ['A']
a[1, 0] = [ 1, 2 ] #=> array a will be ["A", 1, 2]