我是java的新手,我在制作具有类似界面的泛型类时遇到了问题。在LinkedList类的sortedInsert方法中,它在head.value.compareTo(new_node.value)上给出了错误,我在main中创建了一个Linkedlist类的对象,所以根据我的理解head.value应该给我一个员工对象为哪个我我打电话给compareTo。但它仍然给我这个错误。有什么我不明白的理解?或者在这段代码中犯了错误。
无法找到符号 符号:方法compareTo(T)
public class Employee implements Comparable<Employee>
{
private int empID;
private String name;
private int salary;
private boolean manager;
private int subordinates;
public Employee()
{
empID = 0;
name = "";
salary = 0;
manager = false;
subordinates = 0;
}
public Employee(int id , String name , int salary , boolean manager , int sub)
{
empID = id;
this.name = name;
this.salary = salary;
this.manager = manager;
subordinates = sub;
}
public int GetID()
{
return this.empID;
}
public String GetName()
{
return this.name;
}
@Override
public int compareTo(Employee other)
{
if (this.empID < other.empID)
{
return -1;
}
else if (this.empID > other.empID)
{
return 1;
}
else
{
return 0;
}
}
public class LinkedList<T>
{
private int count;
private Node<T> head;
private class Node<T>
{
public T value;
public Node<T> next;
public Node(T data)
{
this.value = data;
this.next = null;
}
}
LinkedList()
{
count = 0;
head = null;
}
void sortedInsert(T data)
{
Node<T> current;
Node<T> new_node = new Node<T>(data);
/* Special case for head node
head.value >= newNode*/
if (head == null || (head.value.compareTo(new_node.value) == 1 || head.value.compareTo(new_node.value) == 0))
{
new_node.next = head;
head = new_node;
}
else {
current = head;
while (current.next != null && (current.next.value.compareTo(new_node.value) == -1))
current = current.next;
new_node.next = current.next;
current.next = new_node;
}
}
答案 0 :(得分:0)
你可以尝试切换到这个:
public class LinkedList<T extends Comparable<T>>
答案 1 :(得分:0)
function fTwo(){
if (localStorage.getItem("myJson") !== null) {
var passedJson = localStorage.getItem("myJson"); //get saved data anytime
}
}
变量不一定是实现Comparable接口的东西。您需要定义head.value
,以便它必须实现LinkedList<T>
(请参阅@ algrid的答案)或在使用Comparable
方法时强制转换它。