Question

我试图使用个人小酒吧制作一个类似于守望先锋的健康栏。所以每个酒吧的健康都是20％。所以会有5个酒吧。第一个酒吧的健康状况为1 - 20％，接下来的比例为21 - 40％等等。但我无法弄明白。这就是我到目前为止所做的：

public static double health = 100;
public static double maxHealth = 100;
//Each bar should only be 20 percent of their health (This one from 80 - 100)
public static double usePercent = maxHealth * 80 / 100;
public static double healthPercent = health / maxHealth * 100;
//Percent of health the bar should be
public static double percentUse = healthPercent - usePercent;

public static void onHealthChange(int newHealth)
{
    double newHealthPercent = newHealth / maxHealth * 100;
    //Percent of health bar should be after updated health
    double newPercentUse = Math.abs(newHealthPercent - usePercent);

    //Making sure that their health is high enough for this bar
    //Ex: if their health is 80+ it would be on the fifth bar
    if(newHealthPercent >= usePercent)
    {
        //The percentage of the bar that should be used
        double percentBar = newPercentUse / percentUse * 100;

        //The size of each bar is 25
        double size = percentBar * 25 / 100;
    }
}

Answer 1

您可以将其想象如下。给定＆＃34;增量＆＃34;，每个柱中的健康量，为20：

对于健康栏1，找到health / 20
对于健康栏2，找到(health - 20) / 20
对于健康栏3，找到(health - 40) / 20
对于健康栏4，找到(health - 60) / 20
对于健康栏5，找到(health - 80) / 20

我们可以概括为：

对于健康栏n，请找到(health - ((n-1) * increment)) / increment

这很好，但如果当前健康状况为100，则第一个健康栏将获得百分比100 / 20 = 500%。我们可以通过＆＃34; clamp＆＃34;来解决这个问题。价值。我们可以去的最低点是0％（你不能有一个负面填充的健康栏），我们可以达到的最高点是100％（你不能有一个过度填充的健康栏）。我们可以使用Java的Math.min和Math.max来实现此目的。

在表示分数时，使用范围0到1而不是0到100通常也更方便。我已经在我的例子中做到了这一点。

我就是这样做的：

private static final int NUM_HEALTH_BARS = 5;

private double health = 35;
private final double maxHealth = 80;

private final HealthBar[] healthBars = /* whatever */;

public void onHealthChange(final int newHealth)
{
    this.health = newHealth;
    updateHealthBars();
}

private void updateHealthBars()
{
    final double increment = maxHealth / NUM_HEALTH_BARS;

    for (int i = 1; i <= NUM_HEALTH_BARS; ++i)
    {
        double howFull = (health - ((i - 1) * increment)) / increment;
        howFull = Math.min(howFull, 1.0);
        howFull = Math.max(howFull, 0.0);

        // howFull is 0 to 1, so times by 100 if you need it as a percentage:

        healthBars[i].setFull(howFull * 100);
    }
}

如何制作带有独立盒子的健康吧？

1 个答案: