Question

我正在尝试为mongoDB的{{1}}框架创建一个复杂的查询。它需要一个以编程方式添加aggregate和$and。

的组件

这是我对象的当前结构：

$or

但是，为了使对象有用，我需要重新构造它，以便它同时使用const inputObject = { "details.blackBottom": { "in": ["A","B","C","D"] }, "details.blackTop": { "in": ["L","M"] }, "details.redBottom": { "in": ["A","B","C","D"] }, "details.redTop": { "in": ["L","M"] }, "details.greenBottom": { "in": ["A","B","C","D"] }, "details.greenTop": { "in": ["L","M"] } }和$or。最终输出应如下所示：

$and

请注意，const outputObject = { "$and": [ { "$or" : [ {"details.blackBottom": { "in": ["A","B","C","D"] }}, {"details.redBottom": { "in": ["A","B","C","D"] }}, {"details.greenBottom": { "in": ["A","B","C","D"] }} ] }, { "$or" : [ {"details.blackTop": { "in": ["L","M"] } }, {"details.redTop": { "in": ["L","M"] } }, {"details.greenTop": { "in": ["L","M"] } } ] } ] }组件按$or和Bottom分组。

如何将Top转换为所需的inputObject？

Answer 1

您可以使用filter和map方法的组合来实现这一目标：

const inputObject = {
    "details.blackBottom": { "in": ["A","B","C","D"] },
    "details.blackTop": { "in": ["L","M"] },
    "details.redBottom": { "in": ["A","B","C","D"] },
    "details.redTop": { "in": ["L","M"] },
    "details.greenBottom": { "in": ["A","B","C","D"] },
    "details.greenTop": { "in": ["L","M"] }
}

const outputObject = {
    $and: ["Bottom", "Top"].map( side => ({
        $or: Object.keys(inputObject)
                   .filter( key => key.endsWith(side) )
                   .map( key => ({ [key]: inputObject[key] }) )
    }) )
};

console.log(outputObject);

.as-console-wrapper { max-height: 100% !important; top: 0; }

通过引用修改Javascript对象

1 个答案: