Question

我一直用PHP创建一些代码，而我服务器的日志一直显示以下错误。代码是我一直在创建的游戏的处理程序。我试图通过研究和应用修复＆＃39;＆＃39;来解决这些问题。但它并没有顺利进行。

未定义索引：#jt in   第160行/usr/share/nginx/Sweater/Sweater/GameHandler.php   未定义的索引：#jt in   第161行/usr/share/nginx/Sweater/Sweater/GameHandler.php   未定义的索引：#jt in   第167行/usr/share/nginx/Sweater/Sweater/GameHandler.php   未定义的索引：＃lt in   第227行/usr/share/nginx/Sweater/Sweater/GameHandler.php

尝试获取非对象的属性   第302行/usr/share/nginx/Sweater/Sweater/GameHandler.php

这是他们的代码：

function handleJoinTable(Array $arrData, Client $objClient) {
    $intPlayer = $arrData[4];
    $tableId = $arrData[2];
    $strUsername = $this->objDatabase->getUsername($intPlayer);
    $seatId = count($this->tablePopulationById[$tableId]) - 1; // Line 160
    if($this->gamesByTableId[$tableId] === null) { // Line 161
        $findFourGame = new FindFour();
        $this->gamesByTableId[$tableId] = $findFourGame;
    }
    $this->tablePopulationById[$tableId][$strUsername]; // Line 167
    $seatId += 1;
    $objClient->sendXt('jt', $objClient->getIntRoom(), $tableId, $seatId);
    $objClient->sendXt('ut', $objClient->getIntRoom(), $tableId, $seatId);
    $this->playersByTableId[$tableId][] = $intPlayer;
    $this->tableId = $tableId;
}


function handleLeaveTable(Array $arrData, Client $objClient) {
        $intPlayer = $arrData[2];
        $tableId = $arrData[3];
        $strUsername = $this->arrClientsByID[$intPlayer]; // Line 227
        unset($objClient->arrPlayer[$intPlayer]);
        $objClient->sendXt('lt', $objClient->getIntRoom(), $strUsername);
    }

function handleGetGame(Array $arrData, Client $objClient) {
    $intPlayer = $arrData[3];
    if($objClient->getExtRoom() == 802) {
        $puckData = $this->rinkPuck;
        $objClient->sendXt('gz', $objClient->getIntRoom(), $puckData);
    } elseif($intPlayer->tableId !== null) { // Line 302
        $tableId = $intPlayer->tableId;
        $playerUsernames = array_keys($this->tablePopulationById[$tableId]);
        @list($firstPlayer, $secondPlayer) = $playerUsernames;
        $boardString = $this->gamesByTableId[$tableId]->convertToString();
        $objClient->sendXt('gz', -1, $firstPlayer, $secondPlayer, $boardString);
    }
}

这里发生了什么？

Answer 1

$this->tablePopulationById[$tableId]

tablePopulationById是一个不包含索引$ tableId的键的数组。

$arrData[3];不包含您期望的任何课程的对象！

在这两种情况下，var_dump他们看看你有什么！

var_dump($this->tablePopulationById);
var_dump($arrData);

PHP注意：未定义的索引错误

1 个答案: