Question

我正在尝试为一个简单的表单实现php。

<?php
$name = $_POST['name'];
$email = $_POST['email'];
$message = $_POST['message'];
$from = 'From: Hola'; 
$to = 'test@yahoo.com'; 
$subject = 'Hola';

$body = "From: $name\n E-Mail: $email\n Message:\n $message";

if ($_POST['submit']) {
if (mail ($to, $subject, $body, $from)) { 
    echo '<p>Your message has been sent!</p>';
} else { 
    echo '<p>Something went wrong, go back and try again!</p>'; 
}
?>

<form class="form" method="post" action="say-hello.php">

    <label>Name</label>
    <input name="name" placeholder="Spongebob" required data-errormessage-value-missing="Whoa, you can't leave this blank!">

    <label>Email</label>
    <input name="email" type="email" placeholder="squarepants@krustykrab.com" required data-errormessage-value-missing="Whoa, you can't leave this blank!" data-errormessage-type-mismatch="Something isn't right...">

    <label>Message</label>
    <textarea name="message" placeholder="Well Hello!" required data-errormessage-value-missing="Whoa, you can't leave this blank!"></textarea>

    <div class="bttnholder">       
    <input class="submit" name="submit" type="submit" value="Submit" placeholder="Send">
    </div>

</form>

我无法弄清楚为什么我的部分PHP会以HTML格式显示，以及为什么我在页面上出现以下错误：

注意：未定义的索引：第35行的C：\ xampp \ htdocs \ sandbox \ say-hello.php中的名称

注意：未定义的索引：第36行的C：\ xampp \ htdocs \ sandbox \ say-hello.php中的电子邮件

注意：未定义的索引：第37行的C：\ xampp \ htdocs \ sandbox \ say-hello.php中的消息

有关此代码有效的任何帮助吗？

以下是第35,36,37行。

$name = $_POST['name'];
$email = $_POST['email'];
$message = $_POST['message'];

Answer 1

您必须先检查要设置的变量。试试这个：

if (isset($_POST['submit'])) {
  $name = $_POST['name'];
  $email = $_POST['email'];
  $message = $_POST['message'];
  $from = 'From: Hola'; 
  $to = 'test@yahoo.com'; 
  $subject = 'Hola';
  if (mail ($to, $subject, $body, $from)) { 
    echo '<p>Your message has been sent!</p>';
  } else { 
    echo '<p>Something went wrong, go back and try again!</p>';
  }
}

Answer 2

要删除通知，您应该将您的php更改为：

<?php
if(isset($_POST['name'])) {
    $name = $_POST['name'];
}
if(isset($_POST['email'])) {
    $email = $_POST['email'];
}
if(isset($_POST['message'])) {
    $message = $_POST['message'];
}
$from = 'From: Hola'; 
$to = 'test@yahoo.com'; 
$subject = 'Hola';

$body = "From: $name\n E-Mail: $email\n Message:\n $message";

if (isset($_SERVER['CONTENT_LENGTH'])) {
    if (mail ($to, $subject, $body, $from)) { 
        echo '<p>Your message has been sent!</p>';
    } else { 
        echo '<p>Something went wrong, go back and try again!</p>'; 
}

Answer 3

$ _POST [＆＃39; submit＆＃39;]已过时，因为您应该检查正确的表单输入。我检查要设置的每个表单输入，而不是为空。如果其中一个为空或未设置 - ＆gt;错误。如果给出所有字段 - ＆gt;发送邮件。

<?php

    $from = 'From: Hola'; 
    $to = 'test@yahoo.com'; 
    $subject = 'Hola';

    if(
        !isset($_POST['name']) || empty($_POST['name']) ||
        !isset($_POST['email']) || empty($_POST['email']) ||
        !isset($_POST['message']) || empty($_POST['message'])
    ){
        echo '<p>Please fill in all fields</p>';
    }else{
        $body = "From: " . $_POST['name'] . "\n E-Mail: " . $_POST['email'] . "\n Message:\n " . $_POST['message'] . "";
        if (mail ($to, $subject, $body, $from)) { 
            echo '<p>Your message has been sent!</p>';
        } else { 
            echo '<p>Something went wrong, go back and try again!</p>'; 
        }
    }

?>

Answer 4

您的邮件功能错误，其中没有“from”参数，如果您想要一个from参数，您的邮件功能应该是这样的：

首先定义标头变量：

$headers = "From: $from";

你的邮件功能：

mail($to,$subject,$body,$headers)

Answer 5

您必须在if语句中插入这些行。

$name = $_POST['name'];
$email = $_POST['email'];
$message = $_POST['message'];
$from = 'From: Hola'; 
$to = 'test@yahoo.com'; 
$subject = 'Hola';

$body = "From: $name\n E-Mail: $email\n Message:\n $message";

加载html页面时，例如名称不存在。单击提交按钮后设置了它。因此，如果将其放在if语句中，脚本将仅在发布提交按钮后读取变量。

无论如何，为了您将来的考虑，这些不是错误，是警告，脚本仍然有效。

Answer 6

以下是代码试试

$from = 'From: owais'; 
$to = 'test@hotmail.com'; 
$subject = 'Testing';
$name=$_POST['name'];
$email=$_POST['email'];
$message=$_POST['message'];

    if(!empty($name) && !empty($email) && !empty($message) )
    {
        $body = "From: " . $_POST['name'] . "\n E-Mail: " . $_POST['email'] . "\n Message:\n " . $_POST['message'] . "";
        if (mail ($to, $subject, $body, $from)) { 
            echo '<p>Your message has been sent!</p>';
        } else { 
            echo '<p>Something went wrong, go back and try again!</p>'; 
        }
    }

PHP表单抛出错误 - 注意：未定义的索引

6 个答案: