Question

我在Grok学习中练习，用Python完成。请问下面的问题和测试用例：

在开始新工作后，您会发现您的工作场所似乎非常多语言。也就是说，很多人似乎能说多种语言。您决定对您的同事进行调查，以找出他们可以说的语言。编写一个程序来输出只能说一种语言的人的名字（他们是单语）。

读入用户的一行或多行输入。每行都是一个空格分隔的同事姓名列表，可以说某种语言。该语言的名称将是第一件事。

第一行输入将始终为英语，您可以假设您工作场所的每个人都会说英语。

以下是您的程序与用户之间的示例交互：

Line: English Tim Nicky James Tara John Ben
Line: German Nicky Tim
Line: Mandarin Tim John
Line: 
James is monolingual.
Tara is monolingual.
Ben is monolingual.

您的程序可以按任何顺序输出您的单语同事的姓名。如果没有单语同事，你的程序应该输出Everyone是多语言的！

Line: English Boris Aleksei Dmitry Ivan
Line: Russian Dmitry Ivan Boris Aleksei
Line: 
Everyone is multilingual!

我已经走了这么远，但我的代码的问题在于它只适用于1,2,3种语言。如果添加更多语言，则会失败。代码：

masterList = []

supportedLanguages = []

userInput = input("Line: ")

while userInput != "":
    splitUserInput = userInput.split()  
    temporaryList = []  
    supportedLanguages.append(splitUserInput[0])
    temporaryList.append(splitUserInput[0])
    splitUserInput.remove(splitUserInput[0])    
    temporaryList.append(splitUserInput)
    masterList.append(temporaryList)
    userInput = input("Line: ")

namesMaster = []

for language in masterList:
    languageCopy = language
    languageCopy.remove(language[0])

    names = set()
    for name in languageCopy[0]:
        names.add(name)

    namesMaster.append(names)

if len(namesMaster) == 1:

    result = namesMaster[0]
    for name in result:
        print(name, " is monolingual.")

elif len(namesMaster) == 2:
    result = namesMaster[0].difference(namesMaster[1])
    print("Everyone is multilingual!")
else:   
    result = namesMaster[0].difference(namesMaster[1], namesMaster[2])

for name in result:
    print(name, " is monolingual.")

Answer 1

使用defaultdict：

设置变量：

from collections import defaultdict
masterList = defaultdict(list)

使用while循环来循环播放input，并为每次变量分配true。

while True:
  userInput = input("Line: ")
  if len(userInput) > 0:
    splitUserInput = userInput.split()
    lang = splitUserInput[0]
    # Everything after the first element is appended.
    for s in splitUserInput[1:]:
      masterList[s].append(lang)
  else:
    break

遍历您的defaultdict以查看是否有任何键只分配了一个值，如果没有，请打印每个人都是多语言的。

all_multilingual = True
for name, langs in masterList.items():
  if len(langs) == 1:
    print(name + " is monolingual.")
    all_multilingual = False
if all_multilingual:
  print("Everyone is multilingual!")

Answer 2

在此Python Grok练习中，目标是使用集合：

a = {1, 2, 3}
b = {3, 4, 5}
print(a | b)  # Union
print(a & b)  # Intersection
print(a - b)  # Difference
print(b - a)  # Difference
print(a ^ b)  # Symmetric difference

Answer 3

仅使用已学到的知识-这就是答案（也是最简单的答案）

monolingual = None

line = input('Line: ')
while line:
  line = line.split()
  names = set(line[1:])
  if monolingual is None:
    monolingual = names
  else:
    monolingual -= names
  line = input('Line: ')

if monolingual:
  for name in monolingual:
    print(name, 'is monolingual.')
else:
  print('Everyone is multilingual!')

Answer 4

line = input("Line: ")
a = set(line.split()[1:])

line = input("Line: ")
while line:
      line = set(line.split()[1:])
      a = a -line
      line = input("Line: ")

if a:
      for person in a:
      print(person + ' is monolingual.')
else:
      print("Everyone is multilingual!")

Python集，单语练习

4 个答案: