我正在尝试在水平和垂直方向上实施sobel算子。但不知何故,我得到了反向输出。我在下面附上的代码。对于水平蒙版
char mask [3][3]= {{-1,-2,-1},{0,0,0},{1,2,1}};
void masking(Mat image){
Mat temImage= image.clone();
for (int i = 1; i < image.rows-1; i++)
{
for (int j = 1; j < image.cols-1; j++)
{
for(int k=0;k<3;k++)
{
int pixel1 = image.at<Vec3b>(i-1,j-1)[k] * -1;
int pixel2 = image.at<Vec3b>(i,j-1)[k] * -2;
int pixel3 = image.at<Vec3b>(i+1,j-1)[k] * -1;
int pixel4 = image.at<Vec3b>(i-1,j)[k] * 0;
int pixel5 = image.at<Vec3b>(i,j)[k] * 0;
int pixel6 = image.at<Vec3b>(i+1,j)[k] * 0;
int pixel7 = image.at<Vec3b>(i-1,j+1)[k] * 1;
int pixel8 = image.at<Vec3b>(i,j+1)[k] * 2;
int pixel9 = image.at<Vec3b>(i+1,j+1)[k] * 1;
int sum = pixel1 + pixel2 + pixel3 + pixel4 + pixel5 + pixel6 + pixel7 + pixel8 + pixel9;
if(sum < 0)
{
sum = 0;
}
if(sum > 255)
sum = 255;
temImage.at<Vec3b>(i,j)[k] = sum;
}
}
}
//printf("conter = %d",counter);
imshow( "Display", temImage );
imwrite("output1.png",temImage);
}
我的输出为
垂直掩码
char mask [3][3]= {{-1,0,1},{-2,0,2},{-1,0,1}};
void masking(Mat image){
Mat temImage= image.clone();
for (int i = 1; i < image.rows-1; i++)
{
for (int j = 1; j < image.cols-1; j++)
{
for(int k=0;k<3;k++)
{
int pixel1 = image.at<Vec3b>(i-1,j-1)[k] * -1;
int pixel2 = image.at<Vec3b>(i,j-1)[k] * 0;
int pixel3 = image.at<Vec3b>(i+1,j-1)[k] * 1;
int pixel4 = image.at<Vec3b>(i-1,j)[k] * -2;
int pixel5 = image.at<Vec3b>(i,j)[k] * 0;
int pixel6 = image.at<Vec3b>(i+1,j)[k] * 2;
int pixel7 = image.at<Vec3b>(i-1,j+1)[k] * -1;
int pixel8 = image.at<Vec3b>(i,j+1)[k] * 0;
int pixel9 = image.at<Vec3b>(i+1,j+1)[k] * 1;
int sum = pixel1 + pixel2 + pixel3 + pixel4 + pixel5 + pixel6 + pixel7 + pixel8 + pixel9;
if(sum < 0)
{
sum = 0;
}
if(sum > 255)
sum = 255;
temImage.at<Vec3b>(i,j)[k] = sum;
}
}
}
//printf("conter = %d",counter);
imshow( "Display", temImage );
imwrite("output1.png",temImage);
}
我的输出为
主要功能见
int main( int argc, char** argv ){
Mat input_image = imread("sobel1.jpg",1);
masking(input_image);
waitKey(0);
return 0;
}
根据指南https://www.tutorialspoint.com/dip/sobel_operator.htm,我应该得到反向输出。任何人都可以帮助我
原始图片是