我正在尝试延长一个月的参与ID超过两次的租户的valid_till日期。
refid, referrer_id, referrer_bonus_amount, referral_valid, valid_from, valid_till
1 2 2500 1 2015-07-05 2015-09-05
2 3 2500 1 2015-07-05 2015-09-05
3 5 1000 0 2015-12-13 2016-02-13
4 6 2500 0 2016-04-25 2016-06-24
5 10 1000 1 2015-07-01 2015-09-01
6 12 2500 1 2015-05-12 2015-07-12
7 13 2500 0 2015-08-05 2015-10-05
8 20 1000 1 2016-02-05 2016-04-05
9 2 2500 0 2015-08-12 2015-09-12
10 5 91000 1 2016-02-18 2016-04-18
11 20 1500 1 2016-06-19 2016-08-19
12 9 2500 0 2015-11-15 2016-01-15
13 13 91000 1 2016-02-01 2016-04-01
14 5 1000 1 2016-04-25 2016-06-24
答案 0 :(得分:1)
要update
表(t
)为valid_till
的{{1}}日期添加1个月,refid
出现在referrer_id
两次以上exists()
与having count(*) > 2
:
update t
set valid_till = dateadd(month,1,valid_till)
output inserted.*
from t
where exists (
select 1
from t as i
where i.referrer_id = t.refid
group by referrer_id
having count(*) > 2
)
rextester演示:http://rextester.com/WXZC31875
输出:
+-------+-------------+-----------------------+----------------+------------+------------+
| refid | referrer_id | referrer_bonus_amount | referral_valid | valid_from | valid_till |
+-------+-------------+-----------------------+----------------+------------+------------+
| 5 | 10 | 1000 | 1 | 2015-07-01 | 2015-10-01 |
+-------+-------------+-----------------------+----------------+------------+------------+