Question

DECLARE @startMonth int
DECLARE @endMonth int

DECLARE @startYear int
DECLARE @endYear int

SET @startMonth = 1
SET @endMonth =5

SET @startYear =2014
SET @endYear =2015

SELECT * FROM Table 
         WHERE (YEAR(Date)>=@startYear AND MONTH(Date) >= @startMonth)
              AND (YEAR(Date)<=@endYear AND MONTH(Date) <= @endMonth)

这显然是2014-01-01至2014-05-31之间任何日期的结果

和2014-01-01至2015-05-31

但我希望从2014-01-01到2015-05-31获得任何日期。

我该如何更改查询？我应该写下面的内容？

SELECT * FROM Table 
         WHERE Date>=DATEFROMPARTS ( @startYear, @startMonth, 1 ) 
           AND Date <= DATEFROMPARTS ( @endYear, @endMonth, 31 ))

然后我最终得到的问题是，如果@endMonth不包含31天。然后我必须创建另一个检查以确保结束日期的正确数量。

我相信必须有更好的方法来写这个。我很感激你的帮助。

Answer 1

SELECT * 
FROM your_table 
WHERE Date >= DATEFROMPARTS(@startYear, @startMonth, 1)
  AND Date <  DATEFROMPARTS(@endYear, @endMonth + 1, 1)

Answer 2

SELECT *
FROM
    <table_name>
WHERE
    date BETWEEN DATEFROMPARTS(@startYear,@startMonth,1) AND EOMONTH(DATEFROMPARTS(@endYear,@endMonth,1));

通过在SQL中使用月份和年份数来查询基于日期范围

2 个答案: