我有一个记录集
AGREEMENTID FeedbackDate DispositionCode
0003SBML00151 2017-03-08 00:00:00.000 PTP
0004SBHL00705 2017-03-17 00:00:00.000 BPTP
0007SBML01987 NULL NULL
0026MSS00108 2017-05-20 00:00:00.000 PTP
0026MSS00108 2017-03-22 00:00:00.000 PTP
0026MSS00108 2016-12-30 00:00:00.000 BPTP
0026MSS00108 2016-12-29 00:00:00.000 BPTP
0026MSS00108 2016-12-28 00:00:00.000 BPTP
0037SBHL02361 NULL NULL
0038SBML00291 2017-05-04 00:00:00.000 PTP
0038SBML00291 2017-04-24 00:00:00.000 BPTP
0038SBML00291 2017-04-11 00:00:00.000 NC
0038SBML00291 2016-12-22 00:00:00.000 PTP
0038SBML00291 2016-12-09 00:00:00.000 DC
所需的输出将是
AGREEMENTID L1 L2 L3 L4 L5
0003SBML00151 PTP NULL NULL NULL NULL
0004SBHL00705 BPTP NULL NULL NULL NULL
0007SBML01987 NULL NULL NULL NULL NULL
0026MSS00108 PTP PTP BPTP BPTP BPTP
0037SBHL02361 NULL NULL NULL NULL NULL
0038SBML00291 PTP BPTP NC PTP DC
SQL架构
Declare @T table(AGREEMENTID varchar(50),FeedbackDate varchar(50),DispositionCode varchar(10))
Insert into @T
Select '0003SBML00151','2017-03-08 00:00:00.000','PTP' union all
Select '0004SBHL00705','2017-03-17 00:00:00.000','BPTP' union all
Select '0007SBML01987',NULL,NULL union all
Select '0026MSS00108','2017-05-20 00:00:00.000','PTP' union all
Select '0026MSS00108','2017-03-22 00:00:00.000','PTP' union all
Select '0026MSS00108','2016-12-30 00:00:00.000','BPTP' union all
Select '0026MSS00108','2016-12-29 00:00:00.000','BPTP' union all
Select '0026MSS00108','2016-12-28 00:00:00.000','BPTP' union all
Select '0037SBHL02361',NULL,NULL union all
Select '0038SBML00291','2017-05-04 00:00:00.000','PTP' union all
Select '0038SBML00291','2017-04-24 00:00:00.000','BPTP' union all
Select '0038SBML00291','2017-04-11 00:00:00.000','NC' union all
Select '0038SBML00291','2016-12-22 00:00:00.000','PTP' union all
Select '0038SBML00291','2016-12-09 00:00:00.000','DC'
Select *
From @T
这是我的尝试
;with cte1 as(
SELECT AGREEMENTID, abc = STUFF(
(SELECT '.' + DispositionCode
FROM @T t1
WHERE t1.AGREEMENTID = t2.AGREEMENTID --and t1.Rn = t2.Rn
FOR XML PATH (''))
, 1, 1, '') from @T t2
group by AGREEMENTID)
--select *
--from cte1
,cte2 as(
select AGREEMENTID,
X= IIF(charindex('.',abc,1) is null,'NULL VALUE',IIF(charindex('.',abc,1) = 0,'SINGLE VALUE','MULTIPLE VALUE'))
--,COL1 = SUBSTRING(abc,1,IIF(charindex('.',abc,1) = NULL,0,IIF(charindex('.',abc,1) = 0,len(abc),(charindex('.',abc,1)-1))))
--,charindex('.',abc,1)
,abc
from cte1)
,cte3 as(
select
AGREEMENTID
,COL1 =IIF(X = 'NULL VALUE', NULL,IIF(X='SINGLE VALUE',SUBSTRING(abc,1,len(abc)),SUBSTRING(abc,1,(charindex('.',abc,1)-1))))
,abc
,OtherCols = IIF(X = 'MULTIPLE VALUE',SUBSTRING(abc,charindex('.',abc,1)+1,len(abc)),'')
from cte2)
select
AGREEMENTID
,L1 = IIF(COL1 is null, '--',COL1)
,l2 = IIF(PARSENAME(OtherCols,4)is null, '--',PARSENAME(OtherCols,4))
,l3 = IIF(PARSENAME(OtherCols,3)is null, '--',PARSENAME(OtherCols,3))
,l4 = IIF(PARSENAME(OtherCols,2)is null, '--',PARSENAME(OtherCols,2))
,l5 = IIF(PARSENAME(OtherCols,1)is null, '--',PARSENAME(OtherCols,1))
From cte3
缺点
a）慢查询
b）以下案例
失败AGREEMENTID FeedbackDate DispositionCode
0002SBML01241 2017-05-04 00:00:00.000 Today
0002SBML01241 2017-04-24 00:00:00.000 PTP
0002SBML01241 2017-04-11 00:00:00.000 PTP
0002SBML01241 2016-12-22 00:00:00.000 PTP
实际
AGREEMENTID L1 l2 l3 l4 l5
0002SBML01241 Today -- PTP PTP PTP
预期
AGREEMENTID L1 l2 l3 l4 l5
0002SBML01241 Today PTP PTP PTP --
答案 0 :(得分：1)
获取结果的示例数据
IF OBJECT_ID('tempdb..#Temp') IS NOT NULL
DROP TABLE #Temp
Declare @T table
(AGREEMENTID varchar(50),
FeedbackDate varchar(50),
DispositionCode varchar(10)
)
Insert into @T
SELECT '0003SBML00151','2017-03-08 00:00:00.000','PTP' union all
SELECT '0004SBHL00705','2017-03-17 00:00:00.000','BPTP' union all
SELECT '0007SBML01987',NULL,NULL union all
SELECT '0026MSS00108','2017-05-20 00:00:00.000','PTP' union all
SELECT '0026MSS00108','2017-03-22 00:00:00.000','PTP' union all
SELECT '0026MSS00108','2016-12-30 00:00:00.000','BPTP' union all
SELECT '0026MSS00108','2016-12-29 00:00:00.000','BPTP' union all
SELECT '0026MSS00108','2016-12-28 00:00:00.000','BPTP' union all
SELECT '0037SBHL02361',NULL,NULL union all
SELECT '0038SBML00291','2017-05-04 00:00:00.000','PTP' union all
SELECT '0038SBML00291','2017-04-24 00:00:00.000','BPTP' union all
SELECT '0038SBML00291','2017-04-11 00:00:00.000','NC' union all
SELECT '0038SBML00291','2016-12-22 00:00:00.000','PTP' union all
SELECT '0038SBML00291','2016-12-09 00:00:00.000','DC'
SELECT *,
'L'
+ Cast(Row_number()OVER(partition BY dispositioncode ORDER BY agreementid
)AS
VARCHAR(10)) AS Lcolumn
INTO #temp
FROM @T
动态sql进程获取结果
DECLARE @DyColumn NVARCHAR(max), @DyColumn2 NVARCHAR(max),
@Sql NVARCHAR(max)
SELECT @DyColumn = STUFF((SELECT DISTINCT ', ' + QUOTENAME(lcolumn)
FROM #temp
FOR xml path ('')), 1, 2, '')
SELECT @DyColumn2 = STUFF((SELECT DISTINCT ', ' + 'ISNULL('+QUOTENAME(lcolumn) +','+'''0'''+') AS '++QUOTENAME(lcolumn)
FROM #temp
FOR xml path ('')), 1, 2, '')
SET @Sql=N' SELECT AGREEMENTID,' + @DyColumn2
+ ' FROM ( SELECT * FROM #Temp ) AS Src PIVOT ( MIN(DispositionCode) FOR Lcolumn IN ('
+ @DyColumn + ') )AS Pvt '
PRINT @Sql
EXEC (@Sql)
答案 1 :(得分：1)
我能够实现所需的输出，考虑到你不会有更多级别而不是[L5]，在这种情况下你需要有动态PIVOT解决方案。
对于Dynamic Pivot解决方案，您可以查看Krishnaraj's answer。
SELECT *
FROM
(
Select AGREEMENTID,
DispositionCode,
'L' + CAST(ROW_NUMBER() OVER(Partition By AGREEMENTID ORDER BY FeedbackDate DESC) AS VARCHAR(255)) as RowNum
From @T
) as PivotSource
PIVOT
(
MAX(DispositionCode) FOR RowNum IN ([L1], [L2], [L3], [L4], [L5])
) as Pvt;
答案 2 :(得分：1)
这有助于动态水平：
def appId = 'com.example.one'
def appId2 = 'com.example.two'
if(appId && appId2){
compileOptions.encoding = 'ISO-8859-1'
}else{
compileOptions.encoding = 'UTF-8'
}