SQL Query Pivoting

时间:2009-10-18 07:56:44

标签: tsql

我有一张表格结构(高尔夫记分卡)如下:

HoleID int
CourseID int
Par INT
Distance INT
LowIndex INT
HighIndex INT
Sequence INT (representing the sequence of the hole: 1, 2, 3, ... 18)

本课程有18个洞。

我想转入:

Hole,      1, 2, 3, ... 18
Par,       X, X, X, ... X
Distance,  Y, Y, Y, ... Y
LowIndex,  Z, Z, Z, ... Z
HighIndex, A, A, A, ... A

我可以通过使用游标来实现这一点,但还有更好的方法吗?

4 个答案:

答案 0 :(得分:1)

TSQL直接支持透视。例如,看看herehere

答案 1 :(得分:1)

你可以做到

SELECT HoleID FROM Card WHERE  HoleId =1 ,(SELECT  HoleID   FROM Card WHERE  HoleId =2) , -- etc  

UNION
SELECT Par FROM Card WHERE HoleId = 1, (SELECT Par FROM Card where HoleID=2). --etc
UNION
SELECT Distance FROM Card WHERE HoleId = 1, (SELECT Distance FROM Card where HoleID=2). --etc
UNION
SELECT LowIndex FROM Card WHERE HoleId = 1, (SELECT LowIndex FROM Card where HoleID=2). --etc
UNION
SELECT HIghIndex FROM Card WHERE HoleId = 1, (SELECT HighIndex FROM Card where HoleID=2). --etc

如果你不顾一切地摆脱光标。

确保通过强制转换或其他方式使所有数据类型相同。

答案 2 :(得分:0)

只有第一部分......它会做的。

select [1],[2],[3],[4],[5],[6],[7],[8],[9], [10], [11], [12], [13], [14], [15], [16], [17], [18]
from (Select Sequence, Par FROM holes WHERE CourseID=1) a

PIVOT 
(
    Max(Par)
    FOR [Sequence] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9], [10], [11], [12], [13], [14], [15], [16], [17], [18])

) AS p

答案 3 :(得分:0)

完整清单:

select 'Par', [1],[2],[3],[4],[5],[6],[7],[8],[9], [10], [11], [12], [13], [14], [15], [16], [17], [18]
from (Select Sequence, Par FROM holes WHERE CourseID=1) a

PIVOT 
(
    Max(Par)
    FOR [Sequence] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9], [10], [11], [12], [13], [14], [15], [16], [17], [18])

) AS p

UNION

select 'Distance', [1],[2],[3],[4],[5],[6],[7],[8],[9], [10], [11], [12], [13], [14], [15], [16], [17], [18]
from (Select Sequence, Distance FROM holes WHERE CourseID=1) a

PIVOT 
(
    Max(Distance)
    FOR [Sequence] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9], [10], [11], [12], [13], [14], [15], [16], [17], [18])

) AS p

UNION


select 'LowIndex', [1],[2],[3],[4],[5],[6],[7],[8],[9], [10], [11], [12], [13], [14], [15], [16], [17], [18]
from (Select Sequence, LowIndex FROM holes WHERE CourseID=1) a

PIVOT 
(
    Max(LowIndex)
    FOR [Sequence] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9], [10], [11], [12], [13], [14], [15], [16], [17], [18])

) AS p

UNION

select 'HighIndex', [1],[2],[3],[4],[5],[6],[7],[8],[9], [10], [11], [12], [13], [14], [15], [16], [17], [18]
from (Select Sequence, HighIndex FROM holes WHERE CourseID=1) a

PIVOT 
(
    Max(HighIndex)
    FOR [Sequence] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9], [10], [11], [12], [13], [14], [15], [16], [17], [18])

) AS p