Question

我是Python新手。我有两组数据如下所示。

设置1：

Gmt time,Open,High,Low,Close,Volume
15.06.2017 00:00:00.000,0.75892,0.75933,0.75859,0.75883,4777.4702
15.06.2017 01:00:00.000,0.75885,0.76313,0.75833,0.76207,7452.5601
15.06.2017 02:00:00.000,0.76207,0.76214,0.76106,0.76143,4798.4102
15.06.2017 03:00:00.000,0.76147,0.76166,0.76015,0.76154,4961.4502
15.06.2017 04:00:00.000,0.76154,0.76162,0.76104,0.76121,2977.6399
15.06.2017 05:00:00.000,0.7612,0.76154,0.76101,0.76151,3105.4399
...

设置2：

print(daily['Gmt time'][0].date == hourly['Gmt time'][0].date)

我想在Set 1的同一日期找到Set 2中的行。我试过这个：{{1}}，但我不知道为什么它出来了。是不是有办法比较两组数据的日期（只是日期，不包括时间）？

Answer 1

首先将数据集读入数据帧：

import pandas as pd
df_one = pd.DataFrame.from_csv('data_set_one.csv', index_col=False)
df_two = pd.DataFrame.from_csv('data_set_two.csv', index_col=False)

将日期列转换为日期

df_one['Gmt date'] = pd.to_datetime(df_one['Gmt time']).dt.date
df_two['Gmt date'] = pd.to_datetime(df_two['Gmt time']).dt.date

现在比较两个数据帧：

for i, row in df_one.iterrows():
    df_one_date = row['Gmt date']
    print('df_one_date', df_one_date)
    print(df_two[df_two['Gmt date'] == df_one_date])
    print('----')

目前还不清楚你想如何处理df_one的不同日期以匹配df_two。希望这能让你对如何处理它有足够的了解。

Answer 2

由于使用iterrows可能很慢，因此更好的选择可能是使用merge。

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document.addEventListener('mouseenter', () => replaceImage(mouseEnterImage));

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[0,1,2,3,4,5]

从两组数据中查找相同的日期

2 个答案: