Question

Newbi on XML。尝试从所有DisplayName：s读取Text属性。认为我的问题在Rule元素附近。是一种解决我的问题的方法吗？提前致谢！ //马格努斯

<?xml version="1.0" encoding="utf-16"?>
<AppMgmtDigest xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.microsoft.com/SystemCenterConfigurationManager/2009/AppMgmtDigest">
  <DeploymentType >
    <Requirements>
      <Rule xmlns="http://schemas.microsoft.com/SystemsCenterConfigurationManager/2009/06/14/Rules">
        <Annotation>
          <DisplayName Text="Primary device Equals True"/>
        </Annotation>
      </Rule>
      <Rule xmlns="http://schemas.microsoft.com/SystemsCenterConfigurationManager/2009/06/14/Rules">
        <Annotation>
          <DisplayName Text="Operating system One of {All Windows 10 (64-bit)}"/>
        </Annotation>
      </Rule>
    </Requirements>
  </DeploymentType>
</AppMgmtDigest>





XmlDocument xml = new XmlDocument();
xml.LoadXml(SDMPackageXML);

XmlNamespaceManager ns = new XmlNamespaceManager(xml.NameTable);
ns.AddNamespace("msbld","http://schemas.microsoft.com/SystemCenterConfigurationManager/2009/AppMgmtDigest");
ns.AddNamespace("msbldr","http://schemas.microsoft.com/SystemCenterConfigurationManager/2009/06/14/Rules");

XmlNodeList nodlist = xml.SelectNode("/msbld:AppMgmtDigest/msbld:DeploymentType/msbld:Requirements/msbldr:Rule", ns/@Text);

Answer 1

试试xml linq：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
using System.IO;

namespace ConsoleApplication1
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            StreamReader reader = new StreamReader(FILENAME);
            reader.ReadLine(); //skip the identification line with utf-16
            XElement doc = XElement.Load(reader);

            List<string> text = doc.Descendants().Where(x => x.Name.LocalName == "DisplayName").Select(x => (string)x.Attribute("Text")).ToList();

        }

    }
}

Answer 2

首先，名称空间中有一个拼写错误：xml中的Systems，C＃中的System。

其次，您的代码无法编译。在发布之前，请更正明显的错误。

请试试这个：

// Correct typo
ns.AddNamespace("msbldr",
    "http://schemas.microsoft.com/SystemsCenterConfigurationManager/2009/06/14/Rules");

XmlNodeList nodelst = xml.SelectNodes(
    "/msbld:AppMgmtDigest/msbld:DeploymentType/msbld:Requirements/msbldr:Rule//@Text", ns);

此外，您的xpath可以指定所需属性的确切路径：

"/msbld:AppMgmtDigest/msbld:DeploymentType/msbld:Requirements/msbldr:Rule/msbldr:Annotation/msbldr:DisplayName/@Text"

C＃ - 使用子Xmlns从XML读取属性

2 个答案: