我有一个使用coretext绘制一些文本的视图。一切正常,文字正面朝上,翻转坐标。但是,我还必须回应特定运行的触摸,所以我有以下代码,当点击手势识别器触发时会调用它:
- (void)receivedTap:(UITapGestureRecognizer*)recognizer
{
CGPoint point = [recognizer locationInView:self];
NSLog(@"point = %@", NSStringFromCGPoint(point));
CGContextRef context = UIGraphicsGetCurrentContext();
CFArrayRef lines = CTFrameGetLines(textFrame);
CFIndex lineCount = CFArrayGetCount(lines);
CGPoint origins[lineCount];
CTFrameGetLineOrigins(textFrame, CFRangeMake(0, 0), origins);
for(CFIndex idx = 0; idx < lineCount; idx++)
{
CTLineRef line = CFArrayGetValueAtIndex(lines, idx);
CGRect lineBounds = CTLineGetImageBounds(line, context);
lineBounds.origin.y += origins[idx].y;
if(CGRectContainsPoint(lineBounds, point))
{
CFArrayRef runs = CTLineGetGlyphRuns(line);
for(CFIndex j = 0; j < CFArrayGetCount(runs); j++)
{
CTRunRef run = CFArrayGetValueAtIndex(runs, j);
NSDictionary* attributes = (NSDictionary*)CTRunGetAttributes(run);
BOOL result = NO;
NSURL* url = [attributes objectForKey:kJTextViewDataDetectorLinkKey];
NSString* phoneNumber = [attributes objectForKey:kJTextViewDataDetectorPhoneNumberKey];
NSDictionary* addressComponents = [attributes objectForKey:kJTextViewDataDetectorPhoneNumberKey];
if(url)
{
result = [[UIApplication sharedApplication] openURL:url];
return;
}
else if(phoneNumber)
{
NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"tel://%@", phoneNumber]];
result = [[UIApplication sharedApplication] openURL:url];
return;
}
else if(addressComponents)
{
NSMutableString* address = [NSMutableString string];
NSString* temp = nil;
if((temp = [addressComponents objectForKey:NSTextCheckingStreetKey]))
[address appendString:temp];
if((temp = [addressComponents objectForKey:NSTextCheckingCityKey]))
[address appendString:[NSString stringWithFormat:@"%@%@", ([address length] > 0) ? @", " : @"", temp]];
if((temp = [addressComponents objectForKey:NSTextCheckingStateKey]))
[address appendString:[NSString stringWithFormat:@"%@%@", ([address length] > 0) ? @", " : @"", temp]];
if((temp = [addressComponents objectForKey:NSTextCheckingZIPKey]))
[address appendString:[NSString stringWithFormat:@" %@", temp]];
if((temp = [addressComponents objectForKey:NSTextCheckingCountryKey]))
[address appendString:[NSString stringWithFormat:@"%@%@", ([address length] > 0) ? @", " : @"", temp]];
NSString* urlString = [NSString stringWithFormat:@"http://maps.google.com/maps?q=%@", [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
result = [[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]];
return;
}
}
}
}
}
哪个适用于第一行,例如,我正在进行一些数据检测的网址。我轻拍它,Mobile Safari就像我期望的那样启动。但是,这仅在项目位于第一行时才有效。我在其他行上看到文字的颜色和下划线(用于地址和电话号码等),我已经验证了相应的数据附加到字符串中的自定义属性,但是当我点击它们时,没有任何事情发生。
我知道我必须以某种方式翻转矩形lineBounds
,但我不知道如何去做。任何帮助将不胜感激。
答案 0 :(得分:1)
实际上你需要做的是反过来迭代lines
。例如,尝试在此代码中替换:
NSArray* tempLines = (NSArray*)CTFrameGetLines(textFrame);
CFIndex lineCount = [tempLines count];//CFArrayGetCount(lines);
NSMutableArray* lines = [NSMutableArray arrayWithCapacity:lineCount];
for(id elem in [tempLines reverseObjectEnumerator])
[lines addObject:elem];
CGPoint origins[lineCount];
答案 1 :(得分:0)
最简单的反转方式
CFArrayRef lines = (CFArrayRef)[[(NSArray *)CTFrameGetLines(frame) reverseObjectEnumerator] allObjects];