Question

我有一个DataFrame

                A              B             C            D
2015-07-18  4.534390e+05  2.990611e+05  5.706540e+05  4.554383e+05   
2015-07-22  3.991351e+05  2.606576e+05  3.876394e+05  4.019723e+05   
2015-08-07  1.085791e+05  8.215599e+04  1.356295e+05  1.096541e+05   
2015-08-19  1.397305e+06  8.681048e+05  1.672141e+06  1.403100e+06  
...

我只是想将所有列相加以获得新的数据帧

      A   B  C  D
sum   s   s  s  s

使用列式和，然后使用to_csv()打印。何时使用

 df.sum(axis=0)
 print(df)


 A       9.099377e+06
 B       5.897003e+06
 C       1.049932e+07
 D       9.208681e+06
 dtype: float64

Answer 1

您可以将1转换为$("your-form-id or event-any-id").on("click", function(event) { event.preventDefault(); var post = new FormData( $("#form-id") ); $.ajax({ url: "url", type: "POST OR GET", dataType: "JSON", data: post, processData: false, contentType: false, success: function (data, status) {}, error: function (xhr, desc, err){} }); });并转置它：

df.sum()

Answer 2

pd.DataFrame的略短版本（由于简化而归功于jezrael）：

In [120]: pd.DataFrame([df.sum()], index=['sum'])
Out[120]: 
             A           B          C          D
sum  2358458.2  1509979.49  2766063.9  2370164.7

Answer 3

使用<div class="container"> <div class="single_tag">First div <div class="dropdown-content"> <a href="#">Link 1</a> <a href="#">Link 2</a> <a href="#">Link 3</a> </div> </div> <div class="single_tag">Second div <div class="dropdown-content"> <a href="#">Link 1</a> <a href="#">Link 2</a> <a href="#">Link 3</a> <a href="#">Link 1</a> <a href="#">Link 2</a> <a href="#">Link 3</a> </div> </div> <div class="single_tag">Third div <div class="dropdown-content"> <a href="#">Link 1</a> <a href="#">Link 2</a> <a href="#">Link 3</a> </div> </div>构造函数：

DataFrame

Answer 4

我认为最简单的是df.agg([sum])

df.agg([sum])
Out[40]:
            A            B          C           D
sum 2358458.2   1509979.49  2766063.9   2370164.7

对列进行求和以形成新的数据帧

4 个答案: