Question

我试图将图像发送到我的服务器以将其存储到mysql数据库。

我尝试使用jQuery发布Formdata并像java MultipartFile一样接收它并将其转换为bytes []。我找到了几种方法，但都没有工作，请有人帮帮我吗？

这是我最好的尝试：

<form>
<input type="file" id="file"/>
<a onclick="uploadImage()"  >Upload</a>
</form>

JS

function uploadImage() {
    var formData = new FormData();
    formData.append('file', $('#file')[0].files[0]);
    $.ajax({
        type : 'POST',
        url : '/admin/uploadImage',
        headers : {
            "X-CSRF-TOKEN" : token
        },
        data : formData,
        cache: false,
        contentType: false,
        processData: false,
    }); 
    alert("proso");
}

和JAVA

@RequestMapping(value = "/uploadImage", method = RequestMethod.POST)
    public void save(@RequestParam("file") MultipartFile file)
    {

        try
        {

            File convFile = new File(file.getOriginalFilename());
            convFile.createNewFile();
            System.out.println("file: " + convFile.getTotalSpace());
            byte[] bFile = new byte[(int) convFile.length()];

            FileInputStream fileInputStream = new FileInputStream(convFile);
            fileInputStream.read(bFile);
            fileInputStream.close();
            Files newFile = new Files();
            newFile.setFileName("4h");
            newFile.setData(bFile);
            filesRepository.save(newFile);
        }
        catch (IOException e)
        {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

    }

有人能帮助我吗？

Answer 1

尝试以下代码

@RequestMapping(value = "/uploadImage", method = RequestMethod.POST)
public void save(MultipartHttpServletRequest request)
{

    try
    {
        Iterator<String> itr = request.getFileNames();
        while(itr.hasNext()) {
            MultipartFile file = request.getFile(itr.next());

            if(file != null) {
                File convFile = new File(file.getOriginalFilename());
                convFile.createNewFile();
               System.out.println("file: " + convFile.getTotalSpace());
               byte[] bFile = new byte[(int) convFile.length()];

               FileInputStream fileInputStream = new 
               FileInputStream(convFile);
               fileInputStream.read(bFile);
               fileInputStream.close();
               Files newFile = new Files();
               newFile.setFileName("4h");
               newFile.setData(bFile);
               filesRepository.save(newFile);
            }
        }
        catch (IOException e)
        {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

}

使用jQuery将映像发布到Spring java作为MultipartFile

1 个答案: