如何将multipartFile作为输入?

时间:2018-07-31 15:27:21

标签: java spring jersey dropwizard

我正在尝试在Java中创建图像上传资源。 我的功能如下:

Response fun(@FormDataParam("json") Employee emp, 
             @FormDataParam("file") MultipartFile file){

}

如果我使用邮递员进行文件输入,则文件的值原来为空。 如果我以InputStream作为参数来代替MultipartFile,它将按预期工作。 我在这里想念东西吗?

1 个答案:

答案 0 :(得分:0)

请求类别:

    import java.util.List;

    import org.springframework.web.multipart.MultipartFile;

    public class UserDataForm {

        private String name;
        private List<MultipartFile> file;

        public String getName() {
            return name;
        }
        public void setName(String name) {
            this.name = name;
        }
        public List<MultipartFile> getFile() {
            return file;
        }
        public void setFile(List<MultipartFile> file) {
            this.file = file;
        }
        @Override
        public String toString() {
            return "UserDataForm [name=" + name + ", file=" + file + "]";
        }
}

第二个配置:

@Bean
public CommonsMultipartResolver multipartResolver() {
    CommonsMultipartResolver resolver = new CommonsMultipartResolver();
    //resolver.setMaxInMemorySize(10000); //Define your max or min file size
    resolver.setDefaultEncoding("utf-8");
    return resolver;
}

控制器层:

    /*you can also remove @ModelAttribute that works same*/
        @RequestMapping(value = "userInfoTest" , method = RequestMethod.POST)
        public ResponseJson getInfo(@ModelAttribute UserDataForm user) {
            response.setResponse("Class Info" + user);
            return response;
        }

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