Question

try:
def function_addition(x,y):
    assert (y!=0)
    total= x/y
    return total
num1=float(input("Write a number :"))
num2=float (input("Write a second number:"))
result=function_addition(num1,num2)
assert (num2 !=0)
print (result)

除了AssertionError：打印（“错误！检查您的输入”）

我写了上面的代码，但我不知道为什么我这样做的结果相同：except ZeroDivisionError: So can I delete assert and replace it by except ZeroDivisionError ? `

Answer 1

assert仅检查条件是否为真并抛出异常。 try/except块可以运行一些语句，并检查是否有任何语句抛出异常，以便您可以在except部分处理它。例子：

assert(1 == 2)

会给你一个AsertionError。

try:
    # some statements
    # ...
except OSError as err:
    #If an OSerror exception is thrown, you can process it here. For example:
    print("OS error: {0}".format(err))

您的代码如下所示：

def function_addition(x,y):
    try:
        assert (y!=0)
    except:
        raise ValueError('y is 0.')
    total= x/y
    return total


num1=float(input("Write a number :"))
num2=float (input("Write a second number:"))
try:
    result=function_addition(num1,num2)
except ValueError as ve:
    print(ve)
else:
    print(result)

如果您将其保存在 fun.py 文件中并运行它，您将获得此输出：

Write a number :1
Write a second number:2
0.5
# Run it again.
Write a number :0
Write a second number:0
y is 0.

try / except和assert有什么区别？

1 个答案: