我的代码中有这个原始数组
[
{
"source": {
"id": 2,
"name": "Cairo"
},
"destination": [
{
"count": 3,
"name": "Alex",
"price": 2000,
"discount": null,
"distance": 12,
"new": false
},
{
"count": 4,
"name": "Alex",
"price": 2000,
"discount": null,
"distance": 12,
"new": false
}
]
},
{
"source": {
"id": 1,
"name": "Zagazig"
},
"destination": [
{
"count": 1,
"name": "Alex",
"price": 200,
"discount": null,
"distance": 100,
"new": false
},
{
"count": 1,
"name": "Cairo",
"price": 1000,
"discount": null,
"distance": 100,
"new": false
},
{
"count": 1,
"name": "Cairo",
"price": 1000,
"discount": null,
"distance": 100,
"new": false
}
]
}
]
在目标数组中，如果在像alex或cairo这样的每个对象中重复名称，我想将它合并到一个对象中，只有一个名为cairo的对象，以及一个名为alex的对象，并计算或者使用计数键
我想要这个结果................ ................
[
{
"source": {
"id": 2,
"name": "Cairo"
},
"destination": [
{
"count": 7,
"name": "Alex",
"price": 2000,
"discount": null,
"distance": 12,
"new": false
}
]
},
{
"source": {
"id": 1,
"name": "Zagazig"
},
"destination": [
{
"count": 1,
"name": "Alex",
"price": 200,
"discount": null,
"distance": 100,
"new": false
},
{
"count": 2,
"name": "Cairo",
"price": 1000,
"discount": null,
"distance": 100,
"new": false
},
]
}
]
答案 0 :(得分：0)
如果您只需要在名称相同时对计数求和，则只需迭代每个数组中的每个目标项，当您找到重复的名称时，只需将计数添加到上一个值即可。它将为您提供一个具有所需输出的新数组：
$a = [
array(
"source" => array(
"id" => 2,
"name" => "Cairo"
),
"destination" => [
array(
"count" => 3,
"name" => "Alex",
"price" => 2000,
"discount" => null,
"distance" => 12,
"new" => false
),
array(
"count" => 4,
"name" => "Alex",
"price" => 2000,
"discount" => null,
"distance" => 12,
"new" => false
)
]
),
array(
"source" => array(
"id" => 1,
"name" => "Zagazig"
),
"destination" => [
array(
"count" => 1,
"name" => "Alex",
"price" => 200,
"discount" => null,
"distance" => 100,
"new" => false
),
array(
"count" => 1,
"name" => "Cairo",
"price" => 1000,
"discount" => null,
"distance" => 100,
"new" => false
),
array(
"count" => 1,
"name" => "Cairo",
"price" => 1000,
"discount" => null,
"distance" => 100,
"new" => false
)
]
)
];
$new_array = array();
foreach ($a as $e) {
$tmp = array();
foreach ($e['destination'] as $d) {
if (isset($tmp[$d['name']])) {
$tmp[$d['name']]['count'] += $d['count'];
} else {
$tmp[$d['name']] = $d;
}
}
array_push($new_array, array(
'source' => $e['source'],
'destination' => $tmp
));
}
echo json_encode($new_array);
输出结果为：
[
{
"source":{
"id":2,
"name":"Cairo"
},
"destination":{
"Alex":{
"count":7,
"name":"Alex",
"price":2000,
"discount":null,
"distance":12,
"new":false
}
}
},
{
"source":{
"id":1,
"name":"Zagazig"
},
"destination":{
"Alex":{
"count":1,
"name":"Alex",
"price":200,
"discount":null,
"distance":100,
"new":false
},
"Cairo":{
"count":2,
"name":"Cairo",
"price":1000,
"discount":null,
"distance":100,
"new":false
}
}
}
]
答案 1 :(得分：0)
我建议将任务分成小部分，你可以更好地理解，然后向上移动。
我会帮助你完成内部数组，这是最简单的任务，你会看到一切都会变得更清晰。
所以如果你得到这个json集合：
ReadAsync("qux")您可以解码：
$json_easy = '[
{
"count": 1,
"name": "Alex",
"price": 200,
"discount": null,
"distance": 100,
"new": false
},
{
"count": 1,
"name": "Cairo",
"price": 1000,
"discount": null,
"distance": 100,
"new": false
},
{
"count": 1,
"name": "Cairo",
"price": 1000,
"discount": null,
"distance": 100,
"new": false
}
]';
然后创建一个新数组：
$easy_decode = json_decode($json_easy, true);
如果你仔细观察，你会看到你现在可以在你的php代码中委托你自己的一个函数，并用你喜欢的任何标准对数组中的任何值求和。创建函数后，您可以使用更多for或foreach循环开始在数组中向上移动。