Question

所以，我有两个分离的数组，它们始终具有相同数量的项目，看起来像这样：

array1 = ["Chicken","Chicken","Beef","Shrimp","Beef","Chicken"]
array2 = [2,3,4,1,3,2]

我该如何对所有相应项目的值求和：

Chicken: 7
Beef: 7
Shrimp: 1

欢呼

Answer 1

您可以尝试

let array1 =["Chicken","Chicken","Beef","Shrimp","Beef","Chicken"]
let array2 = [2,3,4,1,3,2]

let op = array1.reduce((output,current,index)=>{
    if(output[current]){
      output[current] +=array2[index];
    } else {
      output[current] = array2[index];
    }
    return output;
},{})

console.log(op);

Answer 2

您可以使用.map()和.reduce()方法来获取结果对象：

let array1 = ["Chicken", "Chicken", "Beef", "Shrimp", "Beef", "Chicken"];
let array2 = [2, 3, 4, 1, 3, 2];

let result = array1.map((v, i) => [v, array2[i]])
                   .reduce((r, [k, v]) => (r[k] = (r[k] || 0) + v, r), {});

console.log(result);

参考：

Answer 3

您可以使用单 Array.reduce来做到这一点：

    @Configuration
  @ComponentScan({"abc.department.common.configs.mongo","abc.department.common.configs.security.web"})
    public class MyServiceConfigs {
    }

或细分且更具可读性的格式：

const keys = ["Chicken","Chicken","Beef","Shrimp","Beef","Chicken"]
const vals = [2,3,4,1,3,2]

console.log(keys.reduce((r,c,i) => 
   (r[keys[i]] = (r[keys[i]] || 0) + vals[i], r), {}))

将键数组与值数组合并，如果键相同则求和

3 个答案: