Question

我有一张桌子“剧院”。其中（theater_name，area_name，station）是复合键。在表“cubelists”中，我有列（thtr_name，area，stn），它们将被引用（table_name，area_name，station）表“剧院”。 / p>

这里的问题是表“剧院”中的列 - （theater_name，area_name，station）的组合是唯一的，因为它是复合键。但每个列分别不是唯一的。

然后我如何从表“cubelists”中引用这些列？

Schema::create('theaters', function (Blueprint $table) {

        $table->string('theater_name');
        $table->string('area_name');
        $table->string('station');
        $table->primary(array('theater_name','area_name','station'));
        $table->text('address');
        $table->bigInteger('phno');
        $table->string('contact_person');

    });



  public function up()
    {
    //
    Schema::create('cubelists', function (Blueprint $table) {
        $table->string('mvie_name');
        $table->foreign('mvie_name')->references('movie_name')->on('movies');
        $table->string('thtr_name');

        $table->string('area');

        $table->string('stn');

        $table->foreign(array('thtr_name','area','stn'))-
        >references(array('theater_name','area_name','station'))-
        >on('theaters');
        $table->primary(array('mvie_name','thtr_name','area','stn'));
        $table->string('type');
        $table->string('subtype');
        $table->date('validity');
        $table->string('show');

    });

}

如果我提供上述代码，我会收到错误

Migration table created successfully.


  [Illuminate\Database\QueryException]
  SQLSTATE[HY000]: General error: 1005 Can't create table `boras_cachii`.`#sql-a10_
  112` (errno: 150 "Foreign key constraint is incorrectly formed") (SQL: alter tabl
  e `agreements` add constraint agreements_area_name_foreign foreign key (`area_nam
  e`) references `cubelists` (`area`))



  [PDOException]
  SQLSTATE[HY000]: General error: 1005 Can't create table `boras_cachii`.`#sql-a10_
  112` (errno: 150 "Foreign key constraint is incorrectly formed")

Answer 1

您必须首先创建表，然后创建外键。

Schema::create('cubelists', function (Blueprint $table) {
        $table->string('mvie_name');
        $table->string('area');
        $table->string('stn');
        $table->primary(array('mvie_name','thtr_name','area','stn'));
        $table->string('type');
        $table->string('subtype');
        $table->date('validity');
        $table->string('show');

           $table->foreign(array('thtr_name','area','stn'))
            ->references(array('theater_name','area_name','station'))
             ->on('theaters');

           $table->foreign('mvie_name')
           ->references('movie_name')
           ->on('movies');


    });

theaters表必须先迁移cubelists，因为~/.zshrc正在引用它。并确保外键列和引用列的类型或长度相同。

使用复合键错误地形成外键约束

1 个答案: