获取导致异常的异常描述和堆栈跟踪，全部作为字符串

Question

我在Python中看过很多关于堆栈跟踪和异常的帖子。但是还没找到我需要的东西。

我有一大堆Python 2.7代码可能引发异常。我想抓住它并分配给字符串它的完整描述和导致错误的堆栈跟踪（我们只是在控制台上看到的所有内容）。我需要这个字符串将其打印到GUI中的文本框。

这样的事情：

try:
    method_that_can_raise_an_exception(params)
except Exception as e:
    print_to_textbox(complete_exception_description(e))

问题是：什么是函数complete_exception_description？

Answer 1

请参阅traceback模块，特别是format_exc()功能。 Here

import traceback

try:
    raise ValueError
except ValueError:
    tb = traceback.format_exc()
else:
    tb = "No error"
finally:
    print tb

Answer 2

  

获取导致异常的异常描述和堆栈跟踪，全部为字符串

创建一个相当复杂的堆栈跟踪来演示我们获得完整的堆栈跟踪：

def raise_error():
    raise RuntimeError('something bad happened!')

def do_something_that_might_error():
    raise_error()

记录完整的堆栈跟踪

最佳做法是为您的模块设置记录器。它将知道模块的名称，并能够更改级别（以及其他属性，如处理程序）

import logging
logging.basicConfig(level=logging.DEBUG)
logger = logging.getLogger(__name__)

我们可以使用此记录器来获取错误：

try:
    do_something_that_might_error()
except Exception as error:
    logger.exception(error)

哪些日志：

ERROR:__main__:something bad happened!
Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
  File "<stdin>", line 2, in do_something_that_might_error
  File "<stdin>", line 2, in raise_error
RuntimeError: something bad happened!

因此我们得到的输出与出错时的输出相同：

>>> do_something_that_might_error()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 2, in do_something_that_might_error
  File "<stdin>", line 2, in raise_error
RuntimeError: something bad happened!

只获取字符串

如果您真的只想要字符串，请使用traceback.format_exc函数，演示在此处记录字符串：

import traceback
try:
    do_something_that_might_error()
except Exception as error:
    just_the_string = traceback.format_exc()
    logger.debug(just_the_string)

哪些日志：

DEBUG:__main__:Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
  File "<stdin>", line 2, in do_something_that_might_error
  File "<stdin>", line 2, in raise_error
RuntimeError: something bad happened!

Answer 3

>>> import sys
>>> import traceback
>>> try:
...   5 / 0
... except ZeroDivisionError as e:
...   type_, value_, traceback_ = sys.exc_info()
>>> traceback.format_tb(traceback_)
['  File "<stdin>", line 2, in <module>\n']
>>> value_
ZeroDivisionError('integer division or modulo by zero',)
>>> type_
<type 'exceptions.ZeroDivisionError'>
>>>
>>> 5 / 0
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ZeroDivisionError: integer division or modulo by zero

使用 sys.exc_info（）收集traceback模块中的信息和函数以对其进行格式化。 Here是格式化它的一些示例。

整个异常字符串位于：

>>> ex = traceback.format_exception(type_, value_, traceback_)
>>> ex
['Traceback (most recent call last):\n', '  File "<stdin>", line 2, in <module>\n', 'ZeroDivisionError: integer division or modulo by zero\n']

Answer 4

使用Python 3，以下代码将格式化Exception对象，与使用traceback.format_exc()完全相同：

import traceback

try: 
    method_that_can_raise_an_exception(params)
except Exception as ex:
    print(''.join(traceback.format_exception(etype=type(ex), value=ex, tb=ex.__traceback__)))

优点是只需要Exception对象（感谢记录的__traceback__属性），因此可以更容易地作为参数传递给另一个函数进行进一步处理。

Answer 5

对于那些使用 Python-3

的人

使用traceback模块和exception.__traceback__可以按如下方式提取堆栈跟踪：

• 使用traceback.extract_stack()
抓取当前堆栈跟踪
• 删除最后三个元素（因为它们是堆栈中的条目，让我进入我的调试功能）
• 使用__traceback__
从异常对象附加traceback.extract_tb()
• 使用traceback.format_list()
格式化整个内容

import traceback
def exception_to_string(excp):
   stack = traceback.extract_stack()[:-3] + traceback.extract_tb(excp.__traceback__)  # add limit=?? 
   pretty = traceback.format_list(stack)
   return ''.join(pretty) + '\n  {} {}'.format(excp.__class__,excp)

一个简单的演示：

def foo():
    try:
        something_invalid()
    except Exception as e:
        print(exception_to_string(e))

def bar():
    return foo()

当我们致电bar()时，我们会收到以下输出：

  File "./test.py", line 57, in <module>
    bar()
  File "./test.py", line 55, in bar
    return foo()
  File "./test.py", line 50, in foo
    something_invalid()

  <class 'NameError'> name 'something_invalid' is not defined

Answer 6

您也可以考虑使用内置的Python模块cgitb来获取一些非常好的，格式良好的异常信息，包括局部变量值，源代码上下文，函数参数等。

例如，此代码......

import cgitb
cgitb.enable(format='text')

def func2(a, divisor):
    return a / divisor

def func1(a, b):
    c = b - 5
    return func2(a, c)

func1(1, 5)

我们得到了这个异常输出......

ZeroDivisionError
Python 3.4.2: C:\tools\python\python.exe
Tue Sep 22 15:29:33 2015

A problem occurred in a Python script.  Here is the sequence of
function calls leading up to the error, in the order they occurred.

 c:\TEMP\cgittest2.py in <module>()
    7 def func1(a, b):
    8   c = b - 5
    9   return func2(a, c)
   10
   11 func1(1, 5)
func1 = <function func1>

 c:\TEMP\cgittest2.py in func1(a=1, b=5)
    7 def func1(a, b):
    8   c = b - 5
    9   return func2(a, c)
   10
   11 func1(1, 5)
global func2 = <function func2>
a = 1
c = 0

 c:\TEMP\cgittest2.py in func2(a=1, divisor=0)
    3
    4 def func2(a, divisor):
    5   return a / divisor
    6
    7 def func1(a, b):
a = 1
divisor = 0
ZeroDivisionError: division by zero
    __cause__ = None
    __class__ = <class 'ZeroDivisionError'>
    __context__ = None
    __delattr__ = <method-wrapper '__delattr__' of ZeroDivisionError object>
    __dict__ = {}
    __dir__ = <built-in method __dir__ of ZeroDivisionError object>
    __doc__ = 'Second argument to a division or modulo operation was zero.'
    __eq__ = <method-wrapper '__eq__' of ZeroDivisionError object>
    __format__ = <built-in method __format__ of ZeroDivisionError object>
    __ge__ = <method-wrapper '__ge__' of ZeroDivisionError object>
    __getattribute__ = <method-wrapper '__getattribute__' of ZeroDivisionError object>
    __gt__ = <method-wrapper '__gt__' of ZeroDivisionError object>
    __hash__ = <method-wrapper '__hash__' of ZeroDivisionError object>
    __init__ = <method-wrapper '__init__' of ZeroDivisionError object>
    __le__ = <method-wrapper '__le__' of ZeroDivisionError object>
    __lt__ = <method-wrapper '__lt__' of ZeroDivisionError object>
    __ne__ = <method-wrapper '__ne__' of ZeroDivisionError object>
    __new__ = <built-in method __new__ of type object>
    __reduce__ = <built-in method __reduce__ of ZeroDivisionError object>
    __reduce_ex__ = <built-in method __reduce_ex__ of ZeroDivisionError object>
    __repr__ = <method-wrapper '__repr__' of ZeroDivisionError object>
    __setattr__ = <method-wrapper '__setattr__' of ZeroDivisionError object>
    __setstate__ = <built-in method __setstate__ of ZeroDivisionError object>
    __sizeof__ = <built-in method __sizeof__ of ZeroDivisionError object>
    __str__ = <method-wrapper '__str__' of ZeroDivisionError object>
    __subclasshook__ = <built-in method __subclasshook__ of type object>
    __suppress_context__ = False
    __traceback__ = <traceback object>
    args = ('division by zero',)
    with_traceback = <built-in method with_traceback of ZeroDivisionError object>

The above is a description of an error in a Python program.  Here is
the original traceback:

Traceback (most recent call last):
  File "cgittest2.py", line 11, in <module>
    func1(1, 5)
  File "cgittest2.py", line 9, in func1
    return func2(a, c)
  File "cgittest2.py", line 5, in func2
    return a / divisor
ZeroDivisionError: division by zero

Answer 7

对于 Python 3.5 + ：

因此，您可以从异常中获取堆栈跟踪，也可以从任何其他异常中获取。为此使用traceback.TracebackException（只需将ex替换为您的例外）即可：

print("".join(traceback.TracebackException.from_exception(ex).format())

扩展示例和其他实现此目的的功能

import traceback

try:
    1/0
except Exception as ex:
    print("".join(traceback.TracebackException.from_exception(ex).format()) == traceback.format_exc() == "".join(traceback.format_exception(type(ex), ex, ex.__traceback__))) # This is True !!
    print("".join(traceback.TracebackException.from_exception(ex).format()))

输出将是这样的：

True
Traceback (most recent call last):
  File "untidsfsdfsdftled.py", line 29, in <module>
    1/0
ZeroDivisionError: division by zero

Answer 8

我的2美分：

import sys, traceback
try: 
  ...
except Exception, e:
  T, V, TB = sys.exc_info()
  print ''.join(traceback.format_exception(T,V,TB))

Answer 9

如果您希望在不处理异常的情况下获得相同的信息，则可以执行以下操作。然后导入回溯：

try:
    ...
except Exception as e:
    print(traceback.print_tb(e.__traceback__))

我正在使用python 3.7

Answer 10

我定义了以下助手类：

import traceback
class TracedExeptions(object):
    def __init__(self):
        pass
    def __enter__(self):
        pass

    def __exit__(self, etype, value, tb):
      if value :
        if not hasattr(value, 'traceString'):
          value.traceString = "\n".join(traceback.format_exception(etype, value, tb))
        return False
      return True

我以后可以这样使用：

with TracedExeptions():
  #some-code-which-might-throw-any-exception

以后可以像这样消费它：

def log_err(ex):
  if hasattr(ex, 'traceString'):
    print("ERROR:{}".format(ex.traceString));
  else:
    print("ERROR:{}".format(ex));

（背景：由于将Promise与Exception一起使用，我很沮丧，不幸的是，它将一个地方引发的异常传递给另一个地方的on_rejected处理程序，因此很难获得从原始位置追溯）

Answer 11

如果您的目标是使异常和stacktrace消息看起来完全像python抛出错误时一样，则以下内容在python 2 + 3中均适用：

import sys, traceback


def format_stacktrace():
    parts = ["Traceback (most recent call last):\n"]
    parts.extend(traceback.format_stack(limit=25)[:-2])
    parts.extend(traceback.format_exception(*sys.exc_info())[1:])
    return "".join(parts)

# EXAMPLE BELOW...

def a():
    b()


def b():
    c()


def c():
    d()


def d():
    assert False, "Noooh don't do it."


print("THIS IS THE FORMATTED STRING")
print("============================\n")

try:
    a()
except:
    stacktrace = format_stacktrace()
    print(stacktrace)

print("THIS IS HOW PYTHON DOES IT")
print("==========================\n")
a()

它的工作原理是从堆栈中删除最后一个format_stacktrace()调用，然后加入其余的调用。运行时，以上示例给出以下输出：

THIS IS THE FORMATTED STRING
============================

Traceback (most recent call last):
  File "test.py", line 31, in <module>
    a()
  File "test.py", line 12, in a
    b()
  File "test.py", line 16, in b
    c()
  File "test.py", line 20, in c
    d()
  File "test.py", line 24, in d
    assert False, "Noooh don't do it."
AssertionError: Noooh don't do it.

THIS IS HOW PYTHON DOES IT
==========================

Traceback (most recent call last):
  File "test.py", line 38, in <module>
    a()
  File "test.py", line 12, in a
    b()
  File "test.py", line 16, in b
    c()
  File "test.py", line 20, in c
    d()
  File "test.py", line 24, in d
    assert False, "Noooh don't do it."
AssertionError: Noooh don't do it.

Answer 12

如果您想将回溯转换为 dict 列表（对于 python > 3.5）：

from traceback import TracebackException


def list_traceback(exc_value: BaseException):
    result = list()

    # get previous fails, so errors are appended by order of execution
    if exc_value.__context__:
        result += list_traceback(exc_value.__context__)

    # convert Exception into TracebackException
    tbe = TracebackException.from_exception(exc_value)

    # get stacktrace (cascade methods calls)
    error_lines = list()
    for frame_summary in tbe.stack:
        summary_details = {
            'filename': frame_summary.filename,
            'method'  : frame_summary.name,
            'lineno'  : frame_summary.lineno,
            'code'    : frame_summary.line
        }
        error_lines.append(summary_details)

    # append error, by order of execution
    result.append({"error_lines": error_lines,
                   "type"       : tbe.exc_type.__name__,
                   "message"    : str(tbe)})

    return result

这将是（一个例子）结果：

[
   {
      "error_lines": [
         {
            "filename": "/home/demo/file2.py",
            "method": "do_error_2",
            "lineno": 18,
            "code": "a=1/0"
         }
      ],
      "type": "ZeroDivisionError",
      "message": "division by zero"
   },
   {
      "error_lines": [
         {
            "filename": "/home/demo/file_main.py",
            "method": "demo2",
            "lineno": 50,
            "code": "file2.DEMO().do_error_2()"
         },
         {
            "filename": "/home/demo/file2.py",
            "method": "do_error_2",
            "lineno": 20,
            "code": "raise AssertionError(\"Raised inside the except, after division by zero\")"
         }
      ],
      "type": "AssertionError",
      "message": "Raised inside the except, after division by zero"
   }
]