将XAML PathGeometry转换为WPF PathGeometry

时间:2010-12-30 05:58:47

标签: c# wpf xaml pathgeometry

我想要由LineSegment组成的PathGeometry。

所以,我使用第一个代码,但这是错误的。

PathGeometry temp = (PathGeometry)Geometry.Parse(
            "<PathGeometry.Figures>" +
                "<PathFigure StartPoint=\"193.5,283.5\" IsClosed=\"True\">" +
                    "<PathFigure.Segments>" +
                        "<LineSegment Point=\"418.5,283.5\" />" +
                        "<LineSegment Point=\"418.5,508.5\" />" +
                        "<LineSegment Point=\"193.5,508.5\" />" +
                        "<LineSegment Point=\"193.5,283.5\" />" +
                    "</PathFigure.Segments>" +
                "</PathFigure>" +
            "</PathGeometry.Figures>");

如果我使用第二个代码,则不是错误,但它不包含LineSegment。结果将是PolyLineSegment,但我想要LineSegment。

PathGeometry temp = (PathGeometry)Geometry.Parse(
                "M29,329L30,331L31,334L33,336L34,338L36,341L38,343L39,345L41,348L44,352L46,353L47,355L48,356L49,357L49,357L50,358L50,358L51,357L50,356L51,354L51,350L53,342L54,334L58,320L60,315L61,311L63,308L63,306L64,304L65,303L65,302L66,301L66,301L66,301L66,301L66,301L66,301L66,301");

如何将XAML PathGeometry转换为WPF PathGeometry?

由于

1 个答案:

答案 0 :(得分:9)

解析XAML的代码不正确,您需要使用XAML阅读器并将结果转换为所需类型。 e.g:

System.Windows.Shapes.Path newPath = (System.Windows.Shapes.Path)System.Windows.Markup.XamlReader.Parse("<Path xmlns='http://schemas.microsoft.com/winfx/2006/xaml/presentation'  Width='20' Height='80' Stretch='Fill' Fill='#FF000000' Data='M 20,25.2941L 20,29.4118L 15.9091,29.4118L 15.9091,40L 12.2727,40L 12.2727,29.4118L 2.54313e-006,29.4118L 2.54313e-006,25.6985L 13.4872,7.62939e-006L 15.9091,7.62939e-006L 15.9091,25.2941L 20,25.2941 Z M 12.2727,25.2941L 12.2727,5.28493L 2.09517,25.2941L 12.2727,25.2941 Z M 20,65.2941L 20,69.4118L 15.9091,69.4118L 15.9091,80L 12.2727,80L 12.2727,69.4118L -5.08626e-006,69.4118L -5.08626e-006,65.6985L 13.4872,40L 15.9091,40L 15.9091,65.2941L 20,65.2941 Z M 12.2727,65.2941L 12.2727,45.2849L 2.09517,65.2941L 12.2727,65.2941 Z ' HorizontalAlignment='Left' VerticalAlignment='Top' Margin='140,60,0,0'/>");
LayoutRoot.Children.Add(newPath);

如果您使用代码隐藏,是否有任何理由要解析XAML代码段?您可以通过编程方式创建路径,如下所示:

Path path = new Path();
PathGeometry geometry = new PathGeometry();
PathFigure figure = new PathFigure();
figure.StartPoint = new Point(10,10); 
figure.Segments.Add(new LineSegment()
{
  Point = new Point (20, 20)
});

// e.g. add more segments here

geometry.Figures.Add(figure);
path.Data = geometry;

路径由几何组成,由图形组成,由图形组成!

如果要在代码中使用简化路径数据,可以使用通用值转换器:

http://www.scottlogic.co.uk/blog/colin/2010/07/a-universal-value-converter-for-wpf/