需要一些帮助 - 我认为这不是太困难,但有心理障碍。 我试图将数据帧与一列转换为两列,并用逗号分隔。以下是我正在使用的代码:
log_model2coeff_df = log_model2coeff_df['lol'].apply(lambda x :pd.Series(x.split(',')))
+-----------------------------------------------+
| lol |
+-----------------------------------------------+
| ('Principal', array([-0.00088419])) |
| ('age', array([ 0.01724407])) |
| ('Male', array([-0.31822202])) |
| ('High School or Below', array([-0.0003084])) |
| ('Master or Above', array([ 0.02205005])) |
| ('college', array([ 0.10759677])) |
+-----------------------------------------------+
我希望它看起来像:
+---------------------------------------------------+
| lol | lol2 |
+---------------------------------------------------+
| ('college' | array([ 0.10759677])) |
| ('age' | array([ 0.01724407])) |
| ('Principal' | array([-0.00088419])) |
| ('Master or Above' | array([ 0.02205005])) |
| ('Male' | array([-0.31822202])) |
| ('High School or Below' | array([-0.0003084])) |
+----------------------------------------------------
Thanks in advance
答案 0 :(得分:0)
最简单的方法是将分割结果存储在中间变量中。
split = df['lol'].str.split(',')
df['lol'] = split.apply(lambda x: x[0])
df['lol2'] = split.apply(lambda x: x[1])