Question

我有这个SQL查询：

SELECT
  HALLS_REGISTRATION.ID,
  (
    CAST(
        (SELECT
           HALLS_REGISTRATION.MONEY_RECEIVED_NUMERIC
         FROM
           HALLS_REGISTRATION
         WHERE
           HALLS_REGISTRATION.ID = 2)
        AS DECIMAL
    )
    +
    (SELECT
       SUM(
           CAST(
               HALLS_REGISTRATION_PAID.PAID_MONEY
               AS DECIMAL
           )
       )
     FROM
       HALLS_REGISTRATION_PAID
     WHERE
       HALLS_REGISTRATION_PAID.REGISTRATION_ID = HALLS_REGISTRATION.ID
    )
  )
FROM HALLS_REGISTRATION;

这很好用，但这不是我想要的。我想要的是用外部选择返回的2替换第10行的HALLS_REGISTRATION.ID，所以当我尝试这种方法时，

SELECT
  HALLS_REGISTRATION.ID,
  (
    CAST(
        (SELECT
           HALLS_REGISTRATION.MONEY_RECEIVED_NUMERIC
         FROM
           HALLS_REGISTRATION
         WHERE
           HALLS_REGISTRATION.ID = ROOT.HALLS_REGISTRATION.ID)
        AS DECIMAL
    )
    +
    (SELECT
       SUM(
           CAST(
               HALLS_REGISTRATION_PAID.PAID_MONEY
               AS DECIMAL
           )
       )
     FROM
       HALLS_REGISTRATION_PAID
     WHERE
       HALLS_REGISTRATION_PAID.REGISTRATION_ID = HALLS_REGISTRATION.ID
    )
  )
FROM HALLS_REGISTRATION AS ROOT;

DataGrip将Root视为未解析的符号，我在执行时遇到此错误

[42S22] [42122]未找到“HALLS_REGISTRATION.ID”栏; SQL 语句：

我希望查询与H2，MySQL或两者兼容。

Answer 1

此：

SELECT
  HALLS_REGISTRATION.ID,
  (
    CAST(
        (SELECT
           HALLS_REGISTRATION.MONEY_RECEIVED_NUMERIC
         FROM
           HALLS_REGISTRATION, HALLS_REGISTRATION_PAID
         WHERE
           WHERE
       HALLS_REGISTRATION_PAID.REGISTRATION_ID = HALLS_REGISTRATION.ID)
        AS DECIMAL
    )
    +
    (SELECT
       SUM(
           CAST(
               HALLS_REGISTRATION_PAID.PAID_MONEY
               AS DECIMAL
           )
       )
     FROM
       HALLS_REGISTRATION_PAID
     WHERE
       HALLS_REGISTRATION_PAID.REGISTRATION_ID = HALLS_REGISTRATION.ID
    )
  )
FROM HALLS_REGISTRATION;

可能会做你想做的事。

Answer 2

错误消息不是x，而是第二个子ROOT。

SELECT

我不确定，您需要所有这些子查询...

尝试这样的事情：

SELECT
  ROOT.ID,
  (
    CAST(
        (SELECT
           HALLS_REGISTRATION.MONEY_RECEIVED_NUMERIC
         FROM
           HALLS_REGISTRATION
         WHERE
           HALLS_REGISTRATION.ID = ROOT.ID)
        AS DECIMAL
    )
    +
    (SELECT
       SUM(
           CAST(
               PAID_MONEY
               AS DECIMAL
           )
       )
     FROM
       HALLS_REGISTRATION_PAID
     WHERE
       REGISTRATION_ID = ROOT.ID
    )
  )
FROM HALLS_REGISTRATION AS ROOT;

SQL与相关子查询的麻烦

2 个答案: