我需要创建一个jQuery增量/减量循环。
所以我在这里发布了vanilla JavaScript，请有人将此更改为jQuery代码。
var incomeTicker = 60;
window.setInterval(function(){
if (incomeTicker > 0){
incomeTicker--;
document.getElementById("incomeTicker").innerHTML = "Next Profit In : " + incomeTicker + " seconds";
// other code implemented as long as incomTicker > 0
}
if (incomeTicker <= 1){
//code that is implemented when incomeTicker <=1
incomeTicker = 60;
//code that is implemented when incomeTicker <=1
}
}, 1000);<span class = "incomeTicker" id = "incomeTicker" > Next Profit In : 100 seconds</span>
任何人都可以帮助将其翻译成jQuery吗？它必须递减，然后在循环完成后重置，如代码段
所示答案 0 :(得分：2)
您可以使用解决方案https://jsfiddle.net/vh0obhz6/
var incomeTicker = 60;
window.setInterval(function(){
if (incomeTicker > 1){
incomeTicker--;
$("#incomeTicker").html(`Next Profit In : ${incomeTicker} seconds`);
}else{
incomeTicker = 60;
}
}, 1000);<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<span class = "incomeTicker" id = "incomeTicker" > Next Profit In : 100 seconds</span>
答案 1 :(得分：2)
你应该使用更多的jQuery，它会做所有事情。
以下是您如何添加更多jQuery
$.incomeTicker = 60;
(function rec() {
$.each((new Array($.incomeTicker)).fill(0), function(i) {
var sec = Math.abs(i - $.incomeTicker);
$('#incomeTicker').delay(1000).queue(function(n) {
$(this).html("Next Profit In : " + sec + " seconds");
n(); if (sec === 1) rec();
});
});
})();<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="incomeTicker"></div>
答案 2 :(得分：1)
var incomeTicker = 60;
window.setInterval(function(){
if (incomeTicker > 0){
incomeTicker--;
$("#incomeTicker").html("Next Profit In : " + incomeTicker + " seconds");
// other code implemented as long as incomTicker > 0
}
if (incomeTicker <= 1){
//code that is implemented when incomeTicker <=1
incomeTicker = 60;
//code that is implemented when incomeTicker <=1
}
}, 1000);