case语句中“< =”附近的Verilog语法错误

时间:2017-08-08 20:10:02

标签: verilog

在这段代码中:

    reg [4:0] status_led = 5'b00100;
    case (status_led)
        default: begin                   
            if (rotation) begin
                status_led[4] <= status_led[3];
                status_led[3] <= status_led[2];
                status_led[2] <= status_led[1];
                status_led[1] <= status_led[0];
                status_led[0] <= status_led[4];
            end else if (~rotation) begin
                status_led[4] <= status_led[0];
                status_led[3] <= status_led[4];
                status_led[2] <= status_led[3];
                status_led[1] <= status_led[2];
                status_led[0] <= status_led[1];
            end
        end
    endcase

我在&lt; =“附近收到错误”语法错误。为什么这是一个错误?

0 个答案:

没有答案
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