Question

我正在使用两个表。

ft_field_options
ID | option_value | option_name | option_order | LIST_ID

通过以下查询，我可以从今天所有设施中获取所有“提交”的列表，其中list_id等于1.如果发送重复提交，则仅显示最近提交的内容。

问题：此查询仅显示今天提交的设施列表及其后续数据。如何显示今天未提交的设施列表并显示空白或空值？

SELECT t1.facility_id, t2.option_name, t2.option_order, t1.admits, 
t1.reporting_date, t1.last_modified_date, t1.discharges, t1.census, 
t1.pending, DATE_FORMAT(t1.reporting_date,'%m/%d/%Y') AS nicedate
FROM ft_form_1 t1
LEFT JOIN ft_field_options t2
ON (t1.facility_id = t2.option_value AND t2.list_id = 1)
WHERE (DATE_FORMAT(t1.reporting_date,'%m/%d/%Y') = 
DATE_FORMAT(NOW(),'%m/%d/%Y')) AND (t1.last_modified_date=(
SELECT MAX(last_modified_date)
FROM ft_form_1
WHERE facility_id = t1.facility_id))
ORDER BY option_order ASC

Answer 1

你的问题是如此简单，只需按照你的选择，你可以通过测试找到你的答案，并在没有任何关于mysql的知识的情况下多次运行

SELECT t1.facility_id, t2.option_name, t2.option_order, t1.admits, 
t1.reporting_date, t1.last_modified_date, t1.discharges, t1.census, 
t1.pending, DATE_FORMAT(t1.reporting_date,'%m/%d/%Y') AS nicedate
FROM ft_form_1 t1
LEFT JOIN ft_field_options t2
ON (t1.facility_id = t2.option_value AND t2.list_id = 1)
WHERE (DATE_FORMAT(t1.reporting_date,'%m/%d/%Y') != 
DATE_FORMAT(NOW(),'%m/%d/%Y')) AND (t1.last_modified_date=(
SELECT MAX(last_modified_date) AND (t2.optaion_name IS NULL or t2.opation_name = "")
FROM ft_form_1
WHERE facility_id = t1.facility_id))
ORDER BY option_order ASC

我在你的代码中添加了一些东西，就在这里你运行它并自己添加你需要的东西

MYSQL - 显示包括空值在内的所有行

1 个答案: