我试图连接我的Spring 4&使用JNDI Datasource在Amazon Beanstalk中托管的基于Hibernate 4的Web应用程序与Amazon RDS中的数据库。我使用SSH连接到我的EC2环境,并将以下内容放在/usr/share/tomcat8/conf/context.xml文件中;
<Resource
auth="Container"
driverClassName="com.mysql.jdbc.Driver"
name="jdbc/TestDatabase"
password="abc123"
type="javax.sql.DataSource"
url="xyz.com:3306/test_jndi"
username="abc123"/>
在我的Hibernate配置文件中,我使用了以下内容;
@Bean
public LocalSessionFactoryBean sessionFactory() {
LocalSessionFactoryBean sessionFactory = new LocalSessionFactoryBean();
sessionFactory.setDataSource(dataSource());
sessionFactory.setPackagesToScan(new String[] { "com.example.spring.model" });
sessionFactory.setHibernateProperties(hibernateProperties());
return sessionFactory;
}
@Bean
public DataSource dataSource() {
try {
return (DataSource) new
JndiTemplate().lookup("don't know what to provide");
} catch (NamingException e) {
e.printStackTrace();
return null;
}
}
private Properties hibernateProperties() {
Properties properties = new Properties();
properties.put("hibernate.dialect", environment.getRequiredProperty("hibernate.dialect"));
properties.put("hibernate.show_sql", environment.getRequiredProperty("hibernate.show_sql"));
properties.put("hibernate.format_sql", environment.getRequiredProperty("hibernate.format_sql"));
return properties;
}
@Bean
@Autowired
public HibernateTransactionManager transactionManager(SessionFactory s) {
HibernateTransactionManager txManager = new HibernateTransactionManager();
txManager.setSessionFactory(s);
return txManager;
}
我对JNDI在内部提供的内容感到困惑;
JndiTemplate().lookup("don't know what to provide");
我能够成功连接到Amazon RDS数据库,同时使用我本地tomcat的context.xml文件中的上述配置本地保存我的代码,并进行以下查找;
JndiTemplate().lookup("java:comp/env/jdbc/TestDatabase");
但是当我在Amazon Beanstalk中托管我的代码时,同样的查找功能无效。它给了我以下例外情况;
org.springframework.beans.factory.BeanCreationException:
Error creating bean with name 'transactionManager' defined in class path resource [com/example/spring/config/HibernateConfiguration.class]:
Invocation of init method failed; nested exception is org.hibernate.service.UnknownUnwrapTypeException:
Cannot unwrap to requested type [javax.sql.DataSource]
请!任何人,帮助我。