Question

我有一个对象：

public class Species : IEntity<int>
{
     public int Id { get; set; }
     public string Name { get; set; }
     public SpeciesCategory Category { get; set; }
     public WetlandIndicator WetlandIndicator { get; set; }
}

public class SpeciesCategory : IEntity<int>
{
     public int Id { get; set; }
     public string Name { get; set; }
}

public class WetlandIndicator : IEntity<string>
{
     public string Id { get; set; }
     public string Designation { get; set; }
     public bool Status { get; set; }
}

但是，当我使用Dapper调用以下查询时：

SELECT 
    [Species].*, 
    [SpeciesType].*, 
    [WetlandIndicator].Code AS Id, 
    [WetlandIndicator].Designation 
FROM 
    ((([Watershed].[Vegetation].[Species] INNER JOIN [Vegetation].[SpeciesCategory] 
        ON [Watershed].[Vegetation].[Species].[SpeciesCategoryId] = [Vegetation].[SpeciesCategory].[Id]) INNER JOIN [Watershed].[Vegetation].[SpeciesType] 
        ON [Watershed].[Vegetation].[Species].[SpeciesTypeId] = [Vegetation].[SpeciesType].[Id]) INNER JOIN [Watershed].[Vegetation].[WetlandIndicator] 
        ON [Vegetation].[Species].[WetlandIndicatorCode] = [Vegetation].[WetlandIndicator].[Code])

我在使用多映射时收到确认，请确保使用splitOn属性。我是谁，但我仍然收到错误。所以我假设我有一些使用错误或合成错误。持续出错的代码如下：

public async Task<IEnumerable<SpeciesDomain>> GetAllSpecies(string query) =>
        await dbConnection.QueryAsync<Species, SpeciesCategory, WetlandIndicator, SpeciesDomain>(query, (species, speciesCategory, wetlandIndicator) =>
        {
            species.SpeciesCategory = speciesCategory;
            species.WetlandIndicator = wetlandIndicator;
            return species;
        }, splitOn: "Id, Code");

重要说明：默认情况下，Dapper使用Id，这就是我将Code重命名为Id的原因，但即使使用Code或重命名，我仍然会收到多映射错误。

Answer 1

看起来您只需要从splitOn中删除“代码”：“Id，Code”。您的查询将其重命名为“Id”。

Dapper也使用“Id”作为默认值，因此无需指定。

Dapper能够通过假设来分割返回的行您的Id列名为Id或id。如果您的主键不同或者你想在除Id之外的点拆分行，使用可选的splitOn参数。

以下是验证的快速测试：

using (var conn = new SqlConnection(@"Data Source=.\sqlexpress;Integrated Security=true; Initial Catalog=foo"))
{
    var result = conn.Query<Species, SpeciesCategory, WetlandIndicator, Species>(
        "select Id = 11, Name = 'Foo', Id = 22, Name = 'Bar', Id = 33, Designation = 'House Cat' ", 
        (species, speciesCategory, wetlandIndicator) =>
    {
        species.Category = speciesCategory;
        species.WetlandIndicator = wetlandIndicator;
        return species;
    }).First();

    Assert.That(result.Id, Is.EqualTo(11));

    Assert.That(result.Category.Id, Is.EqualTo(22));
    Assert.That(result.Category.Name, Is.EqualTo("Bar"));

    Assert.That(result.WetlandIndicator.Id, Is.EqualTo(33));
    Assert.That(result.WetlandIndicator.Designation, Is.EqualTo("House Cat"));
}

按不同字段和类型更新到演示分组

public class Species
{
    public int Id { get; set; }
    public string Name { get; set; }
    public SpeciesCategory Category { get; set; }
    public WetlandIndicator WetlandIndicator { get; set; }
}

public class SpeciesCategory
{
    public int Id { get; set; }
    public string Name { get; set; }
}

public class WetlandIndicator
{
    public string Code { get; set; }
    public string Designation { get; set; }
    public bool Status { get; set; }
}

using (var conn = new SqlConnection(@"Data Source=.\sqlexpress;Integrated Security=true; Initial Catalog=foo"))
{
    var result = conn.Query<Species, SpeciesCategory, WetlandIndicator, Species>(
        "select Id = 11, Name = 'Foo', Id = 22, Name = 'Bar', Code = 'X', Designation = 'House Cat' ", 
        (species, speciesCategory, wetlandIndicator) =>
    {
        species.Category = speciesCategory;
        species.WetlandIndicator = wetlandIndicator;
        return species;
    }, splitOn: "Id, Code").First();

    Assert.That(result.Id, Is.EqualTo(11));

    Assert.That(result.Category.Id, Is.EqualTo(22));
    Assert.That(result.Category.Name, Is.EqualTo("Bar"));

    Assert.That(result.WetlandIndicator.Code, Is.EqualTo("X"));
    Assert.That(result.WetlandIndicator.Designation, Is.EqualTo("House Cat"));
}

Answer 2

所以，我发现它失败的主要原因。 Dapper不喜欢在splitOn和int之间交替的string参数。通过强制所有这些统一起来，它起作用了。我注意到的另一个问题是，如果你有一个名为Code的列，它反映了一个主键但SQL没有设置为关系标识符，那么它也会出错。

经过纠正后没问题。

Dapper Multi Mapping

2 个答案: