继续运行“如果使用多映射API,请确保在下面的代码块中出现错误以外的其他密钥时设置splitOn参数”:
var accounts = DbConnection.Query<Account, Branch, Application, Account>(
"select Accounts.*, SplitAccount = '', Branches.*, SplitBranch = '', Applications.*" +
" from Accounts" +
" join Branches" +
" on Accounts.BranchId = Branches.BranchId" +
" join Applications" +
" on Accounts.ApplicationId = Applications.ApplicationId" +
" where Accounts.AccountId <> 0",
(account, branch, application) =>
{
account.Branch = branch;
account.Application = application;
return account;
}, splitOn : "SplitAccount, SplitBranch"
).AsQueryable();
我正在使用SplitAccount和SplitBranch for splitOn作为解决方法。
我错过了什么?
由于
修改
我已经清理了一下我的测试,下面是一个轻量级的类和一个新的查询:
public class AccountLight
{
public int AccountId { get; set; }
public string AccountNumber { get; set; }
public BranchLight Branch { get; set; }
public ApplicationLight Application { get; set; }
}
public class BranchLight
{
public int BranchId { get; set; }
public string BranchNumber { get; set; }
}
public class ApplicationLight
{
public int ApplicationId { get; set; }
public string ApplicationCode { get; set; }
}
var accounts2 = DbConnection.Query<AccountLight, BranchLight, ApplicationLight, AccountLight>(
"select Accounts.AccountId, Accounts.AccountNumber," +
" Branches.BranchId, Branches.BranchNumber," +
" Applications.ApplicationId, Applications.ApplicationCode" +
" from Accounts" +
" inner join Branches" +
" on Accounts.BranchId = Branches.BranchId" +
" inner join Applications" +
" on Accounts.ApplicationId = Applications.ApplicationId" +
" where Accounts.AccountId <> 0",
(account, brach, application) =>
{
account.Branch = brach;
account.Application = application;
return account;
},
commandType: CommandType.Text,
splitOn: "AccountId, BranchId"
).AsQueryable();
答案 0 :(得分:21)
经过几个小时的Dapper源代码调试后,我终于找到了问题并且非常有趣。
当提供多个splitOn字段时,Dapper会根据逗号进行拆分,例如: var splits = splitOn.Split(',')。ToArray()。然后它循环遍历所有记录集字段,并根据上面的数组将它们拆分为对象;漂亮的海峡前进。
现在有趣的部分:当我提供我的splitOn字段时,我在逗号之后有一个额外的SPACE,例如“AccountId,BranchId”和那个小空间是原因。在Split()之后,BranchId字段包含一个额外的空格,并且无法与记录集中的任何字段匹配。
有两种解决方法:
这是代码快照:
private static Func<IDataReader, object>[] GenerateDeserializers(Type[] types, string splitOn, IDataReader reader)
{
int current = 0;
var splits = splitOn.Split(',').ToArray();
var splitIndex = 0;
Func<Type, int> nextSplit = type =>
{
var currentSplit = splits[splitIndex].Trim();
if (splits.Length > splitIndex + 1)
{
splitIndex++;
}
更新
以上修复已合并:https://github.com/SamSaffron/dapper-dot-net/commit/399db17e5aa6f1eefaf8fdccff827020be8e6cbb