Question

即使从表单传递数据后，我也收到NOT NULL约束错误。我使用ajax发布数据。我检查了request.POST和网络请求选项卡。两者都显示store_contact_number中包含数据。

这是我的代码

class ListStore(FormView):
    form_class = StoreForm
    template_name = 'Store/list-store.html'

    def form_invalid(self, form):
        if self.request.is_ajax():
            print('ajax form error', form.errors)
            response = {
                'error': form.errors
            }
            return JsonResponse(response, status=400)
        else:
            return super(ListStore, self).form_invalid(form.errors)

    def form_valid(self, form):
        success_message = "Thank you for listing your store. We Welcome you."
        store, created = Store.objects.get_or_create(merchant=self.request.user)
        if self.request.is_ajax():
            response = {
                'result': success_message
            }
            return JsonResponse(response)
        else:
            message.success(self.request, success_message)
            return self.render_to_response(self.get_context_data())



class Store(models.Model):
    merchant = models.ForeignKey(User, blank=False, null=False)
    token = models.CharField(default=token_generator, max_length=20, unique=True, editable=False)
    name_of_legal_entity = models.CharField(max_length=250, blank=False, null=False)
    pan_number = models.CharField(max_length=20, blank=False, null=False)
    registered_office_address = models.CharField(max_length=200)
    name_of_store = models.CharField(max_length=100)
    email = models.EmailField(blank=False, null=False)
    store_contact_number = models.PositiveIntegerField(blank=False, null=False)


$('.list-store-form').on('submit', function(event) {
    event.preventDefault(); // preventing from the brwoser default behavior for form submission
    var form = $(this);
    console.log(form);
    $.ajax({
        async: true,
        url: form.attr('action'),
        data: form.serialize(),
        type: 'POST',
        dataType: 'json',
        headers: {
            'X-CSRFToken': window.csrf_token
        },

        success: function(data) {
            if (data.form_is_valid) {
                alert('Store Listed');
            }
            // $('.display').html(
            //  "<div class='ui floating message'> <i class='close icon'></i>" + data.result + '</div>'
            // );
        },

错误在store_contact_number中显示为

/ list / store中的IntegrityError NOT NULL约束失败： Store_store.store_contact_number

<QueryDict: {'store_contact_number': ['98489678'], 'email': ['admin@gmail.com'], 'registered_office_address': ['Delhi'], 'csrfmiddlewaretoken': ['kSaPMgNt'], 'name_of_store': ['BigMart'], 'pan_number': ['98713962'], 'name_of_legal_entity': ['BigMart Pvt Ltd']}>

表格

class StoreForm(forms.ModelForm):
    class Meta:
        model = Store
        exclude = ('is_active', 'token', 'merchant',)

Answer 1

您需要在store = form.save()方法的开头添加form_valid并删除行store, created = Store.objects.get_or_create(merchant=self.request.user)。

编辑：实际上并不是那么简单，因为form.save（）也会因为没有指定merchant字段而失败。您需要覆盖表单的__init__或save方法，以便传入商家。

类似的东西：

def save(self, merchant, *args, **kwargs):
    commit = kwargs.pop('commit', True)
    kwargs['commit'] = False

    store = super().save(*args, **kwargs)
    store.merchant = merchant
    if commit:
        store.save()
    return store

然后使用：

调用它

def form_valid(self, form):
    store = form.save(merchant=self.request.user)
    success_message = "Thank you for listing your store. We Welcome you."

    if self.request.is_ajax():
        response = {
            'result': success_message
        }
        return JsonResponse(response)
    else:
        message.success(self.request, success_message)
        return self.render_to_response(self.get_context_data())

即使传递数据，也不会出现空约束失败错误

1 个答案: