Question

我正在尝试使用AutoIt计算经过的时间（在Excel中两个单元格的日期值之间）：

_DateDiff($sType, $sStartDate, $sEndDate)

我的问题是_DateDiff()不考虑毫秒。它以秒为单位给出了经过的时间，但我希望它在几秒或几毫秒内完成。

Answer 1

你可以自己扩展这个功能。

您可以在* 1000函数之后计算您的值/ 1000。

; #FUNCTION# ====================================================================================================================
; Author ........: Jos van der Zande
; Modified.......:
; ===============================================================================================================================
Func _DateDiff($sType, $sStartDate, $sEndDate)
    ; Verify that $sType is Valid
    $sType = StringLeft($sType, 1)
    If StringInStr("d,m,y,w,h,n,s", $sType) = 0 Or $sType = "" Then
        Return SetError(1, 0, 0)
    EndIf
    ; Verify If StartDate is valid
    If Not _DateIsValid($sStartDate) Then
        Return SetError(2, 0, 0)
    EndIf
    ; Verify If EndDate is valid
    If Not _DateIsValid($sEndDate) Then
        Return SetError(3, 0, 0)
    EndIf
    Local $asStartDatePart[4], $asStartTimePart[4], $asEndDatePart[4], $asEndTimePart[4]
    ; split the StartDate and Time into arrays
    _DateTimeSplit($sStartDate, $asStartDatePart, $asStartTimePart)
    ; split the End  Date and time into arrays
    _DateTimeSplit($sEndDate, $asEndDatePart, $asEndTimePart)
    ; ====================================================
    ; Get the differens in days between the 2 dates
    Local $aDaysDiff = _DateToDayValue($asEndDatePart[1], $asEndDatePart[2], $asEndDatePart[3]) - _DateToDayValue($asStartDatePart[1], $asStartDatePart[2], $asStartDatePart[3])
    ; ====================================================
    Local $iTimeDiff, $iYearDiff, $iStartTimeInSecs, $iEndTimeInSecs
    ; Get the differens in Seconds between the 2 times when specified
    If $asStartTimePart[0] > 1 And $asEndTimePart[0] > 1 Then
        $iStartTimeInSecs = $asStartTimePart[1] * 3600 + $asStartTimePart[2] * 60 + $asStartTimePart[3]
        $iEndTimeInSecs = $asEndTimePart[1] * 3600 + $asEndTimePart[2] * 60 + $asEndTimePart[3]
        $iTimeDiff = $iEndTimeInSecs - $iStartTimeInSecs
        If $iTimeDiff < 0 Then
            $aDaysDiff = $aDaysDiff - 1
            $iTimeDiff = $iTimeDiff + 24 * 60 * 60
        EndIf
    Else
        $iTimeDiff = 0
    EndIf
    Select
        Case $sType = "d"
            Return $aDaysDiff
        Case $sType = "m"
            $iYearDiff = $asEndDatePart[1] - $asStartDatePart[1]
            Local $iMonthDiff = $asEndDatePart[2] - $asStartDatePart[2] + $iYearDiff * 12
            If $asEndDatePart[3] < $asStartDatePart[3] Then $iMonthDiff = $iMonthDiff - 1
            $iStartTimeInSecs = $asStartTimePart[1] * 3600 + $asStartTimePart[2] * 60 + $asStartTimePart[3]
            $iEndTimeInSecs = $asEndTimePart[1] * 3600 + $asEndTimePart[2] * 60 + $asEndTimePart[3]
            $iTimeDiff = $iEndTimeInSecs - $iStartTimeInSecs
            If $asEndDatePart[3] = $asStartDatePart[3] And $iTimeDiff < 0 Then $iMonthDiff = $iMonthDiff - 1
            Return $iMonthDiff
        Case $sType = "y"
            $iYearDiff = $asEndDatePart[1] - $asStartDatePart[1]
            If $asEndDatePart[2] < $asStartDatePart[2] Then $iYearDiff = $iYearDiff - 1
            If $asEndDatePart[2] = $asStartDatePart[2] And $asEndDatePart[3] < $asStartDatePart[3] Then $iYearDiff = $iYearDiff - 1
            $iStartTimeInSecs = $asStartTimePart[1] * 3600 + $asStartTimePart[2] * 60 + $asStartTimePart[3]
            $iEndTimeInSecs = $asEndTimePart[1] * 3600 + $asEndTimePart[2] * 60 + $asEndTimePart[3]
            $iTimeDiff = $iEndTimeInSecs - $iStartTimeInSecs
            If $asEndDatePart[2] = $asStartDatePart[2] And $asEndDatePart[3] = $asStartDatePart[3] And $iTimeDiff < 0 Then $iYearDiff = $iYearDiff - 1
            Return $iYearDiff
        Case $sType = "w"
            Return Int($aDaysDiff / 7)
        Case $sType = "h"
            Return $aDaysDiff * 24 + Int($iTimeDiff / 3600)
        Case $sType = "n"
            Return $aDaysDiff * 24 * 60 + Int($iTimeDiff / 60)
        Case $sType = "s"
            Return $aDaysDiff * 24 * 60 * 60 + $iTimeDiff
    EndSelect
EndFunc   ;==>_DateDiff

如何使用_DateDiff（）来计算毫秒数？

1 个答案: