Question

我想将文件上传到uploads，但每次都会收到此错误消息：

注意：未定义的索引：第3行的/path/to/dir/upload.php中的fileToUpload

HTML文件：

<form action="php/upload.php" method="post" enctype="multipart/form-data">
    <input type="file" name="fileToUpload" id="fileToUpload">
    <input type="submit" value="Upload Image" name="submit">
</form>

PHP文件：

<?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
    $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
    if($check !== false) {
        echo "File is an image - " . $check["mime"] . ".";
        $uploadOk = 1;
    } else {
        echo "File is not an image.";
        $uploadOk = 0;
    }
}
?>

Answer 1

首先，欢迎使用Stack Overflow。

您必须将第3行移至if语句中，因为如果没有帖子，则不会设置全局$_FILES变量。

例如：

<?php
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
    $target_dir = "uploads/";
    $target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
    $uploadOk = 1;
    $imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);

    $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
    if($check !== false) {
        echo "File is an image - " . $check["mime"] . ".";
        $uploadOk = 1;
    } else {
        echo "File is not an image.";
        $uploadOk = 0;
    }
}
?>

即便如此，可能还没有发布文件

所以：

if(isset($_POST["submit"], $_FILES["fileToUpload"])) {

Answer 2

＆＃34; fileToUpload＆＃34;在初始加载时不可用。

试试这个：

<?php
$target_dir = "uploads/";
$uploadOk = 1;
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
    $target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
    $imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);

    $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
    if($check !== false) {
        echo "File is an image - " . $check["mime"] . ".";
        $uploadOk = 1;
    } else {
        echo "File is not an image.";
        $uploadOk = 0;
    }
}
?>

PHP FileToUpload未定义索引错误

2 个答案: